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How to split a string in shell and get the last field
Suppose I have the string 1:2:3:4:5 and I want to get its last field ( 5 in this case). How do I do that using Bash? I tried cut , but I don't know how to specify the last field with -f .
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Most efficient way of making an if-elif-elif-else statement when the else is done the most?
...:
the_thing = 2
elif something == 'there':
the_thing = 3
else:
the_thing = 4
2.py
something = 'something'
options = {'this': 1, 'that': 2, 'there': 3}
for i in xrange(1000000):
the_thing = options.get(something, 4)
3.py
something = 'something'
options = {'t...
Preferred way to create a Scala list
...end is O(1).
– Daniel C. Sobral
Aug 31 '15 at 19:33
@pgoggijr That is not true. First, there's no "change" anywhere, b...
Clang vs GCC - which produces faster binaries? [closed]
...(speed, memory footprint, reliability) of binaries it produces - if gcc -O3 can produce a binary that runs 1% faster, or Clang binaries take up more memory or just fail due to compiler bugs, it's a deal-breaker.
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How to extract a floating number from a string [duplicate]
I have a number of strings similar to Current Level: 13.4 db. and I would like to extract just the floating point number. I say floating and not decimal as it's sometimes whole. Can RegEx do this or is there a better way?
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Getting a map() to return a list in Python 3.x
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Do this:
list(map(chr,[66,53,0,94]))
In Python 3+, many processes that iterate over iterables return iterators themselves. In most cases, this ends up saving memory, and should make things go faster.
If all you're going to do is iterate over thi...
good example of Javadoc [closed]
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How about the JDK source code, but accessed through a 3rd party like docjar? For example, the Collections source.
That way, there's no big download.
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How to download Xcode DMG or XIP file?
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4943
You can find the DMGs or XIPs for Xcode and other development tools on https://developer.apple.c...
Fast permutation -> number -> permutation mapping algorithms
I have n elements. For the sake of an example, let's say, 7 elements, 1234567. I know there are 7! = 5040 permutations possible of these 7 elements.
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