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Flatten nested dictionaries, compressing keys
...ms.append((new_key, v))
return dict(items)
>>> flatten({'a': 1, 'c': {'a': 2, 'b': {'x': 5, 'y' : 10}}, 'd': [1, 2, 3]})
{'a': 1, 'c_a': 2, 'c_b_x': 5, 'd': [1, 2, 3], 'c_b_y': 10}
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How to specify Composer install path?
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140
It seems that you can define the vendor dir to be something else (plugins in your case):
{
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For loop example in MySQL
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145
drop table if exists foo;
create table foo
(
id int unsigned not null auto_increment primary k...
How can I split a string into segments of n characters?
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12 Answers
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How do SO_REUSEADDR and SO_REUSEPORT differ?
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1680
+100
Welco...
Can the Unix list command 'ls' output numerical chmod permissions?
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it almost can ..
ls -l | awk '{k=0;for(i=0;i<=8;i++)k+=((substr($1,i+2,1)~/[rwx]/) \
*2^(8-i));if(k)printf("%0o ",k);print}'
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Add single element to array in numpy
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167
append() creates a new array which can be the old array with the appended element.
I think it...
What's the difference between “groups” and “captures” in .NET regular expressions?
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127
You won't be the first who's fuzzy about it. Here's what the famous Jeffrey Friedl has to say ...
Sequence contains more than one element
... This method will only succeed when the collections contains exactly 0 or 1 element. I believe you are looking for FirstOrDefault which will succeed no matter how many elements are in the collection.
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