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Immutable vs Mutable types

... What? Floats are immutable? But can't I do x = 5.0 x += 7.0 print x # 12.0 Doesn't that "mut" x? Well you agree strings are immutable right? But you can do the same thing. s = 'foo' s += 'bar' print s # foobar The value of the variable changes, but it changes by chang...
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Get the key corresponding to the minimum value within a dictionary

... | answered Jul 19 '10 at 16:21 community wiki ...
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Base64 encoding and decoding in client-side Javascript

... Some browsers such as Firefox, Chrome, Safari, Opera and IE10+ can handle Base64 natively. Take a look at this Stackoverflow question. It's using btoa() and atob() functions. For server-side JavaScript (Node), you can use Buffers to decode. If you are going for a cross-browser solut...
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How can javascript upload a blob?

...? – William Entriken Aug 7 '13 at 2:05 @FullDecent What do you mean? To prompt the user to download a file using the F...
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Converting string from snake_case to CamelCase in Ruby

... 10 Answers 10 Active ...
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How to get a substring of text?

I have text with length ~700. How do I get only ~30 of its first characters? 5 Answers ...
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python numpy ValueError: operands could not be broadcast together with shapes

... user2357112 supports Monica 200k2020 gold badges287287 silver badges373373 bronze badges answered Jul 3 '14 at 22:08 DrVDrV ...
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Converting between datetime, Timestamp and datetime64

... np >>> dt = datetime.utcnow() >>> dt datetime.datetime(2012, 12, 4, 19, 51, 25, 362455) >>> dt64 = np.datetime64(dt) >>> ts = (dt64 - np.datetime64('1970-01-01T00:00:00Z')) / np.timedelta64(1, 's') >>> ts 1354650685.3624549 >>> datetime.utcfromt...
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Is there an alternative to string.Replace that is case-insensitive?

... From MSDN $0 - "Substitutes the last substring matched by group number number (decimal)." In .NET Regular expressions group 0 is always the entire match. For a literal $ you need to string value = Regex.Replace("%PolicyAmount%", "%Pol...
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How to set transform origin in SVG

...lem is, by default, it always applies the transform around the origin at (0, 0) – top left. 6 Answers ...