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How can I get all the request headers in Django?
... request.META variable along with a lot aof other data. What would be the best way to get all the headers that the client sent to my Django application?
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How do I pick randomly from an array?
... does not have sample; neither does ruby-doc. In your opinion, what is the best reference for Ruby, updated to 1.9?
– Paul Hoffer
Aug 15 '10 at 1:15
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Union of dict objects in Python [duplicate]
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Two dictionaries
def union2(dict1, dict2):
return dict(list(dict1.items()) + list(dict2.items()))
n dictionaries
def union(*dicts):
return dict(itertools.chain.from_iterable(dct.items() for dct in dicts))
sh...
Shortcut for creating single item list in C#
In C#, is there an inline shortcut to instantiate a List with only one item.
13 Answers
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Custom ListView click issue on items in Android
So I have a custom ListView object. The list items have two textviews stacked on top of each other, plus a horizontal progress bar that I want to remain hidden until I actually do something. To the far right is a checkbox that I only want to display when the user needs to download updates to their d...
No ConcurrentList in .Net 4.0?
...-32 array and create a new size-64 array. When adding each of the next 32 items, put it in slot a 32-63 of the new array and copy an old item from the size-32 array to the new one. Until the 64th item is added, readers will look in the size-32 array for items 0-31 and in the size-64 array for item...
Visual Studio 2013 hangs when opening a solution
...lly, I had trouble locating an issue but I agree that this is probably the best approach to solving the problem.
– SteveCinq
Feb 21 '17 at 19:58
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Delete/Reset all entries in Core Data?
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This is probably the best solution for reliability. If I wanted to delete some but not all data, I would use this: stackoverflow.com/questions/1077810/…
– Michael Grinich
Apr 7 '11 at 3:10
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How to find all duplicate from a List? [duplicate]
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If you are using LINQ, you can use the following query:
var duplicateItems = from x in list
group x by x into grouped
where grouped.Count() > 1
select grouped.Key;
or, if you prefer it without the syntactic sugar:
var duplica...
How do I merge a list of dicts into a single dict?
...}
As a comprehension:
# Python >= 2.7
{k: v for d in L for k, v in d.items()}
# Python < 2.7
dict(pair for d in L for pair in d.items())
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