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SQL JOIN and different types of JOINs
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TylerH
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answered Nov 30 '13 at 9:34
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pandas three-way joining multiple dataframes on columns
...g) names of people, while all the other columns in each dataframe are attributes of that person.
10 Answers
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How to get all subsets of a set? (powerset)
...e has exactly a powerset recipe for this:
from itertools import chain, combinations
def powerset(iterable):
"powerset([1,2,3]) --> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)"
s = list(iterable)
return chain.from_iterable(combinations(s, r) for r in range(len(s)+1))
Output:
>&...
Better way to sum a property value in an array
...erCollection extends Array {
sum(key) {
return this.reduce((a, b) => a + (b[key] || 0), 0);
}
}
const traveler = new TravellerCollection(...[
{ description: 'Senior', Amount: 50},
{ description: 'Senior', Amount: 50},
{ description: 'Adult', Amount: 75},
{ desc...
What is the purpose of Rank2Types?
I am not really proficient in Haskell, so this might be a very easy question.
6 Answers
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join list of lists in python [duplicate]
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import itertools
a = [['a','b'], ['c']]
print(list(itertools.chain.from_iterable(a)))
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Chrome sendrequest error: TypeError: Converting circular structure to JSON
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It means that the object you pass in the request (I guess it is pagedoc) has a circular reference, something like:
var a = {};
a.b = a;
JSON.stringify cannot convert structures like this.
N.B.: This would be the case with DOM nodes, which h...
Get querystring from URL using jQuery [duplicate]
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From: http://jquery-howto.blogspot.com/2009/09/get-url-parameters-values-with-jquery.html
This is what you need :)
The following code will return a JavaScript Object containing the URL parameters:
// Read a page's GET URL variables and return them ...
Applicatives compose, monads don't
What does the above statement mean? And when is one preferable to other?
5 Answers
5
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How to calculate number of days between two dates
...tps://date-fns.org/
From Moment docs:
var a = moment([2007, 0, 29]);
var b = moment([2007, 0, 28]);
a.diff(b, 'days') // =1
or to include the start:
a.diff(b, 'days')+1 // =2
Beats messing with timestamps and time zones manually.
Depending on your specific use case, you can either
Use ...
