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How to get indices of a sorted array in Python
...
myList = [1, 2, 3, 100, 5]
sorted(range(len(myList)),key=myList.__getitem__)
[0, 1, 2, 4, 3]
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Generating random numbers in Objective-C
...tes. The arc4random() function returns pseudo-
random numbers in the range of 0 to (2**32)-1, and therefore has twice the range of rand(3) and
random(3).
The arc4random_stir() function reads data from /dev/urandom and uses it to permute the S-Boxes via
arc4random_addrandom().
...
Pythonic way to print list items
...isplay each content, I use:
mylist = ['foo', 'bar']
indexval = 0
for i in range(len(mylist)):
print(mylist[indexval])
indexval += 1
Example of using in a function:
def showAll(listname, startat):
indexval = startat
try:
for i in range(len(mylist)):
print(mylist[...
Standardize data columns in R
... - positional standardization ((x-median)/mad)
n3 - unitization ((x-mean)/range)
n3a - positional unitization ((x-median)/range)
n4 - unitization with zero minimum ((x-min)/range)
n5 - normalization in range <-1,1> ((x-mean)/max(abs(x-mean)))
n5a - positional normalization in range <-1...
How do you create different variable names while in a loop? [duplicate]
...
Sure you can; it's called a dictionary:
d = {}
for x in range(1, 10):
d["string{0}".format(x)] = "Hello"
>>> d["string5"]
'Hello'
>>> d
{'string1': 'Hello',
'string2': 'Hello',
'string3': 'Hello',
'string4': 'Hello',
'string5': 'Hello',
'string6': 'Hel...
Access multiple elements of list knowing their index
...hList, ind: [searchList[i] for i in ind]
using the following input:
a = range(0, 10000000)
b = range(500, 500000)
simple python loop was the quickest with lambda operation a close second, mapIndexValues and getIndexValues were consistently pretty similar with numpy method significantly slower a...
Java's L number (long) specification
...teger, which is why when you type in (long) 6000000000 (not in integer's range) it will complain that 6000000000 is not an integer. To correct this, I had to specify 6000000000L . I just learned about this specification.
...
Iterate an iterator by chunks (of n) in Python? [duplicate]
...s handle the last chunk as desired is
[my_list[i:i + chunk_size] for i in range(0, len(my_list), chunk_size)]
Finally, a solution that works on general iterators an behaves as desired is
def grouper(n, iterable):
it = iter(iterable)
while True:
chunk = tuple(itertools.islice(it, n...
Advantages of std::for_each over for loop
....begin(), collection.end(), [](Element& e)
{
foo(e);
});
when the range-based for loop syntax is available:
for(Element& e : collection)
{
foo(e);
}
This kind of syntax has been available in Java and C# for some time now, and actually there are way more foreach loops than classica...
How to iterate through two lists in parallel?
...hese investigations is given below. The sizes of the foo and bar lists had ranged from 10 to 1,000,000 elements.
Results:
For printing purposes: The performances of all the considered approaches were observed to be approximately similar to the zip() function, after factoring an accuracy tolerance o...