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What's the difference between “mod” and “remainder”?
...1, or -3 with remainder 1, the implementation just had to document which. C99 removed the flexibility, so now -5 / 2 is always -2.
– Steve Jessop
Dec 3 '12 at 13:23
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How can I get a count of the total number of digits in a number?
...ast to double) causes a computation error when the input value is exactly -999999999999999999: the LOG10 method returns 20 instead of 19. The LOG10 method also must have a if guard for the case when the input value is zero.
The LOG10 method is quite tricky to get working for all values, which means...
编译错误 error: ‘typeof’ cannot be used as a function - C/C++ - 清泛网 - 专注C/C++及内核技术
... cannot be used as a function。解决方法：修改C编译选项 -std=gnu99，使用GNU99 编译一些开源的C项目，发现typeof关键字不能被识别，报错： error: ‘typeof’ cannot be used as a function。
解决方法：修改C编译选项 -std=gnu99，使用GNU99编译...
DataTable: Hide the Show Entries dropdown but keep the Search box
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Peter Hall
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answered Jun 27 '17 at 11:06
NivNiv
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SQL to find the number of distinct values in a column
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Paul JamesPaul James
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60
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C char array initialization
...e for main() (and you should also use void, i.e., int main(void) { ... }. C99 got rid of this rule, so this code will not compile for C99 and later. The other thing to note here is that starting with C99, if you omit return in main, there is an automatic return 0; placed/implied before the } at main...
Difference between a Structure and a Union
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union foo x;
x.a = 3;
x.b = 'c';
printf("%i, %i\n", x.a, x.b);
prints
99, 99
Why are the two values the same? Because the last 3 bytes of the int 3 are all zero, so it's also read as 99. If we put in a larger number for x.a, you'll see that this is not always the case:
union foo x;
x.a = 387...
#define macro for debug printing in C?
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If you use a C99 or later compiler
#define debug_print(fmt, ...) \
do { if (DEBUG) fprintf(stderr, fmt, __VA_ARGS__); } while (0)
It assumes you are using C99 (the variable argument list notation is not supported in earlier ...
What is the behavior of integer division?
...@Philip Potter: I don't think it was defined in C89, and it isn't in the 1998 C++ standard. In those, of course (a / b) * b + a % b == a had to be satisfied, and the absolute value of a % b had to be less than a, but whether a % b was negative for negative a or b was not specified.
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Why does sizeof(x++) not increment x?
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From the C99 Standard (the emphasis is mine)
6.5.3.4/2
The sizeof operator yields the size (in bytes) of its operand, which may be an expression or the parenthesized name of a type. The size is determined from the type of the ...