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URLEncoder not able to translate space character

... @congliu that's incorrect - you're probably thinking of replaceAll() which works with regex - replace() is simple character sequence replacement. – CupawnTae Sep 25 '13 at 13:57 ...
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Split comma-separated strings in a column into separate rows

...solution, and two additional variants of Jaap's data.table methods. Overall 8 different methods were benchmarked on 6 different sizes of data frames using the microbenchmark package (see code below). The sample data given by the OP consists only of 20 rows. To create larger data frames, these 20...
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Is a URL allowed to contain a space?

Is a URI (specifically an HTTP URL) allowed to contain one or more space characters? If a URL must be encoded, is + just a commonly followed convention, or a legitimate alternative? ...
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What is the difference between integration and unit tests?

I know the so-called textbook definition of unit tests and integration tests. What I am curious about is when it is time to write unit tests... I will write them to cover as many sets of classes as possible. ...
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“sending 'const NSString *' to parameter of type 'NSString *' discards qualifiers” warning

I have Constants NSString, that I want to call like: 3 Answers 3 ...
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How do I check if an element is really visible with JavaScript? [duplicate]

In JavaScript, how would you check if an element is actually visible? 16 Answers 16 ...
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Placeholder in IE9

It seems it's a very well known problem but all the solutions I found on Google don't work on my newly downloaded IE9. 11 A...
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Error installing libv8: ERROR: Failed to build gem native extension

... try this one: gem install libv8 -v '3.16.14.3' -- --with-system-v8 Note : Because libv8 is the interface for the V8 engine used by therubyracer, you may need to use libv8, even if you have V8 installed already. If you wish to use your ow...
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Dual emission of constructor symbols

...rding to the ABI, the mangled name for your Thing::foo() is easily parsed: _Z | N | 5Thing | 3foo | E | v prefix | nested | `Thing` | `foo`| end nested | parameters: `void` You can read the constructor names similarly, as below. Notice how the constructor "name" isn't given, but ...
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How to initialize an array's length in JavaScript?

... Why do you want to initialize the length? Theoretically there is no need for this. It can even result in confusing behavior, because all tests that use the length to find out whether an array is empty or not will report that the array is not empty. Some tests show that settin...