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What's the difference between %s and %d in Python string formatting?
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what do you call these %s, %d, etc?
– Chaine
May 19 '17 at 18:21
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How to pass parameters on onChange of html select
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Thanks, this has worked for me. Basically I want to show the same combobox at different place,so i gave 2 different ids to 2 combobox.Is there anyway, that i can show the same combobox at different place. Any help will be greatly appreciated.
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Return None if Dictionary key is not available
...ldn't work out what I was doing wrong here.
– wobbily_col
Aug 23 '16 at 14:28
@TimPietzcker - can you please explain y...
Using Python String Formatting with Lists
...rmat with print() to iterate a list.
How about this (python 3.x):
sample_list = ['cat', 'dog', 'bunny', 'pig']
print("Your list of animals are: {}, {}, {} and {}".format(*sample_list))
Read the docs here on using format().
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Should sorting logic be placed in the model, the view, or the controller? [closed]
...ble to the end user. I would like to have these values be sorted alphabetically.
12 Answers
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Checking user's homepage in Internet Explorer
...ailed on this MSDN page. That links to this example page demonstrating the API.
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How to write a:hover in inline CSS?
...defining the selection criteria).
Response to the OP's comments:
See Totally Pwn CSS with Javascript for a good script on adding CSS rules dynamically. Also see Change style sheet for some of the theory on the subject.
Also, don't forget, you can add links to external stylesheets if that's an op...
How to generate a random string in Ruby
...).chr }.join
I spend too much time golfing.
(0...50).map { ('a'..'z').to_a[rand(26)] }.join
And a last one that's even more confusing, but more flexible and wastes fewer cycles:
o = [('a'..'z'), ('A'..'Z')].map(&:to_a).flatten
string = (0...50).map { o[rand(o.length)] }.join
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Getting “Cannot read property 'nodeType' of null” when calling ko.applyBindings
...place your javascript wherever it is suited for organization.
See http://api.jquery.com/ready/
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Why does JQuery have dollar signs everywhere?
...ring your using noConflict (more below)
var divs = $("div"); // Find all divs
var divs = jQuery("div"); // Also find all divs, because
console.log($ === jQuery); // "true"
If you don't want to use the alias, you don't have to. And if you want $ to not be an alias for jQuery, you can use noC...