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How to determine the longest increasing subsequence using dynamic programming?
...
407
OK, I will describe first the simplest solution which is O(N^2), where N is the size of the col...
Create space at the beginning of a UITextField
...t 4.2
class TextField: UITextField {
let padding = UIEdgeInsets(top: 0, left: 5, bottom: 0, right: 5)
override open func textRect(forBounds bounds: CGRect) -> CGRect {
return bounds.inset(by: padding)
}
override open func placeholderRect(forBounds bounds: CGRect) ->...
Imply bit with constant 1 or 0 in SQL Server
Is it possible to express 1 or 0 as a bit when used as a field value in a select statement?
8 Answers
...
Is 'float a = 3.0;' a correct statement?
...
It is not an error to declare float a = 3.0 : if you do, the compiler will convert the double literal 3.0 to a float for you.
However, you should use the float literals notation in specific scenarios.
For performance reasons:
Specifically, consider:
float foo(...
In javascript, is an empty string always false as a boolean?
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edited Jun 20 at 9:12
Community♦
111 silver badge
answered Jan 1 '12 at 12:09
...
Java: random long number in 0
...
Starting from Java 7 (or Android API Level 21 = 5.0+) you could directly use ThreadLocalRandom.current().nextLong(n) (for 0 ≤ x < n) and ThreadLocalRandom.current().nextLong(m, n) (for m ≤ x < n). See @Alex's answer for detail.
If you are stuck with Java 6 (or A...
How can I update the current line in a C# Windows Console App?
...
805
If you print only "\r" to the console the cursor goes back to the beginning of the current line...
Cost of exception handlers in Python
...e just tried the following:
import timeit
statements=["""\
try:
b = 10/a
except ZeroDivisionError:
pass""",
"""\
if a:
b = 10/a""",
"b = 10/a"]
for a in (1,0):
for s in statements:
t = timeit.Timer(stmt=s, setup='a={}'.format(a))
print("a = {}\n{}".format(a,s))
...
How to use Active Support core extensions
I have Active Support 3.0.3 installed and Rails 3.0.3 with Ruby 1.8.7.
5 Answers
5
...
GoTo Next Iteration in For Loop in java
...d would start the next iteration upon invocation
For Example
for(int i= 0 ; i < 5; i++){
if(i==2){
continue;
}
System.out.print(i);
}
This will print
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