Im having a problem with removing non-utf8 characters from string, which are not displaying properly. Characters are like this 0x97 0x61 0x6C 0x6F (hex representation) ...

... main that must be allowed: int main() // (1) int main(int, char*[]) // (2) In (1), there are no parameters. In (2), there are two parameters and they are conventionally named argc and argv, respectively. argv is a pointer to an array of C strings representing the arguments to...

...a quicker/alternative/"better" way to initialize a string from a vector of chars? 7 Answers ...

...rticular character. Click on the Windows Tool-bar Menu (icon like C:.) and select Properties -> Font. Try some other fonts to see if they display your character properly: share | improve this a...

... Won't this add up to three '=' chars? It appears that there will only be 0, 1, or 2 of these. – Kirk Liemohn Aug 4 '09 at 17:10 1 ...

...n address aligned for any standard type no larger than n, and if T isn't a character type then new T[n] is only required to return an address aligned for T. But this is only relevant when you're playing implementation-specific tricks like using the bottom few bits of a pointer to store flags, or ot...

...bytes */ /* 2 padding bytes */ int i; /* 4 bytes */ char c; /* 1 byte */ /* 3 padding bytes */ }; struct Y { int i; /* 4 bytes */ char c; /* 1 byte */ /* 1 padding byte */ short s; /* 2 bytes */ }; struct Z { int i; /* 4 bytes ...

...act that adjacent string literals are concatenated by the compiler: const char *text = "This text is pretty long, but will be " "concatenated into just a single string. " "The disadvantage is that you have to quote " "each part, and newlines must be literal as " "usual."; The indentatio...

... { 　C041() : c_(0x01) {} 　virtual void foo() { c_ = 0x02; } 　char c_; }; struct C100 : public virtual C041 { 　C100() : c_(0x02) {} 　char c_; }; struct C101 : public virtual C041 { 　C101() : c_(0x03) {} 　char c_; }; struct C110 : public C100, public C101 ...