大约有 16,317 项符合查询结果(耗时:0.0221秒) [XML]

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UnicodeDecodeError, invalid continuation byte

Why is the below item failing? Why does it succeed with "latin-1" codec? 10 Answers 10...
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string to string array conversion in java

I have a string = "name"; I want to convert into a string array. How do I do it? Is there any java built in function? Manually I can do it but I'm searching for a java built in function. ...
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Difference between web server, web container and application server

Please tell me the Difference between web server, web container and application server. 8 Answers ...
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How can I do time/hours arithmetic in Google Spreadsheet?

How do I do time/hour arithmetic in a Google spreadsheet? 11 Answers 11 ...
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Regex to match only letters

How can I write a regex that matches only letters? 20 Answers 20 ...
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Make an image width 100% of parent div, but not bigger than its own width

I’m trying to get an image (dynamically placed, with no restrictions on dimensions) to be as wide as its parent div, but only as long as that width isn’t wider than its own width at 100%. I’ve tried this, to no avail: ...
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What could cause java.lang.reflect.InvocationTargetException?

... You've added an extra level of abstraction by calling the method with reflection. The reflection layer wraps any exception in an InvocationTargetException, which lets you tell the difference between an exception actually caused by a failure in the reflection call (maybe your argumen...
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JavaScript chop/slice/trim off last character in string

...e accepted answer, but as per the conversations below, the slice syntax is much clearer: let str = "12345.00"; str = str.slice(0, -1); console.log(str); share | improve this answer ...
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Python 3 ImportError: No module named 'ConfigParser'

I am trying to pip install the MySQL-python package, but I get an ImportError . 18 Answers ...
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Spring JPA @Query with LIKE

I'm trying to make a method in CrudRepository that will be able to give me list of users, whose usernames are LIKE the input parameter(not only begin with, but also contains it). I tried to use method "findUserByUsernameLike(@Param("username") String username)" but as it is told in Spring document...