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How to convert list of key-value tuples into dictionary?
...zip it. ValueError: dictionary update sequence element #0 has length 1916; 2 is required
THAT is your actual question.
The answer is that the elements of your list are not what you think they are. If you type myList[0] you will find that the first element of your list is not a two-tuple, e.g. ('A...
Install a module using pip for specific python version
On Ubuntu 10.04 by default Python 2.6 is installed, then I have installed Python 2.7. How can I use pip install to install packages for Python 2.7.
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Convert command line arguments into an array in Bash
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Actually your command line arguments are practically like an array already. At least, you can ...
Numpy: Get random set of rows from 2D array
I have a very large 2D array which looks something like this:
7 Answers
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Filter dict to contain only certain keys?
...ctionary comprehension.
If you use a version which lacks them (ie Python 2.6 and earlier), make it dict((your_key, old_dict[your_key]) for ...). It's the same, though uglier.
Note that this, unlike jnnnnn's version, has stable performance (depends only on number of your_keys) for old_dicts of any...
A fast method to round a double to a 32-bit int explained
... source code, I noticed that Lua uses a macro to round a double to a 32-bit int . I extracted the macro , and it looks like this:
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TCP 的那些事儿（上） - 更多技术 - 清泛网 - 专注C/C++及内核技术
...序号来拼接数据）。
对于4次挥手，其实你仔细看是2次，因为TCP是全双工的，所以，发送方和接收方都需要Fin和Ack。只不过，有一方是被动的，所以看上去就成了所谓的4次挥手。如果两边同时断连接，那就会就进入到CLOSING...
Elegant Python function to convert CamelCase to snake_case?
...more):
def camel_to_snake(name):
name = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name)
return re.sub('([a-z0-9])([A-Z])', r'\1_\2', name).lower()
print(camel_to_snake('camel2_camel2_case')) # camel2_camel2_case
print(camel_to_snake('getHTTPResponseCode')) # get_http_response_code
print(camel_to_s...
Minimizing NExpectation for a custom distribution in Mathematica
...ur definition above into simple functions:
pdf[a_, b_, m_, s_, x_] := (1/(2*(a + b)))*a*b*
(E^(a*(m + (a*s^2)/2 - x))*Erfc[(m + a*s^2 - x)/(Sqrt[2]*s)] +
E^(b*(-m + (b*s^2)/2 + x))*Erfc[(-m + b*s^2 + x)/(Sqrt[2]*s)])
pdf2[a_, b_, m_, s_, x_] := pdf[a, b, m, s, Log[x]]/x;
If we plot pdf2 ...
Find and kill a process in one line using bash and regex
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25 Answers
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