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How do I check two or more conditions in one ?
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edited May 23 '17 at 11:54
Community♦
111 silver badge
answered Dec 2 '11 at 11:44
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Resolving LNK4098: defaultlib 'MSVCRT' conflicts with
... own CRT version to get their job done. It is located in c:\windows\system32, you cannot reliably use it for your own programs, its CRT headers are not available anywhere. The CRT DLL used by your program has a different name (like msvcrt90.dll).
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In tmux can I resize a pane to an absolute value
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answered Apr 23 '13 at 0:26
dcatdcat
1,09699 silver badges66 bronze badges
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The term 'Get-ADUser' is not recognized as the name of a cmdlet
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edited May 13 '15 at 7:40
answered Jul 9 '13 at 12:50
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In mongoDb, how do you remove an array element by its index?
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138
There is no straight way of pulling/removing by array index. In fact, this is an open issue ht...
python requests file upload
...http://example.com', files=files).prepare().body.decode('ascii'))
--c226ce13d09842658ffbd31e0563c6bd
Content-Disposition: form-data; name="upload_file"; filename="file.txt"
--c226ce13d09842658ffbd31e0563c6bd--
Note the filename="file.txt" parameter.
You can use a tuple for the files mapping val...
Remove large .pack file created by git
...s/original | git update-ref --stdin
# or, for older git versions (e.g. 1.8.3.1) which don't support --stdin
# git update-ref $(git for-each-ref --format='delete %(refname)' refs/original)
git reflog expire --expire=now --all
git gc --aggressive --prune=now
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What linux shell command returns a part of a string? [duplicate]
...urpose. I want to be able to do something like this...
substr "abcdefg" 2 3 - prints cde .
6 Answers
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Cannot simply use PostgreSQL table name (“relation does not exist”)
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307
From what I've read, this error means that you're not referencing the table name correctly. O...
Retrieving the last record in each group - MySQL
...erflow August data dump. I'll use that for benchmarking. There are 1,114,357 rows in the Posts table. This is running on MySQL 5.0.75 on my Macbook Pro 2.40GHz.
I'll write a query to find the most recent post for a given user ID (mine).
First using the technique shown by @Eric with the GROUP BY...