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My pull request has been merged, what to do next?
...ontribute to'.
It is easier to:
delete your fix branch (actually, it is now deleted for you) on your fork (and in your local cloned repo: see "Delete a Git branch both locally and remotely")
git pull upstream master (if master was the branch in which your fix has been integrated: the merge will b...
configure: error: C compiler cannot create executables
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Command line Tools packages ars now available at: developer.apple.com/downloads
– Danny D'Amours
Sep 11 '14 at 23:56
3
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Handling file renames in git
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In git 1.9.1 git status now behaves like git commit.
– Jacques René Mesrine
Oct 5 '15 at 16:11
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Issue with virtualenv - cannot activate
...cannot.
It might just be syntax or folder location, but I am stumped right now.
21 Answers
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How to see which commits in one branch aren't in the other?
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And you wouldn't know of a way to get cherry to mark or exclude equivalent commits, would you? cherry seems like a plumbing command, but doesn't (appear to) offer many options. For what I'm currently in the middle of, git cherry gives me fal...
Using async-await on .net 4
... http://blogs.msdn.com/b/bclteam/archive/2013/04/17/microsoft-bcl-async-is-now-stable.aspx.
You can read about the previous version here: http://blogs.msdn.com/b/lucian/archive/2012/04/24/async-targeting-pack.aspx.
As this pack is officially supported, I now believe the best option for targeting X...
Making interface implementations async
...Async();
IIO asSync = asAsync;
Console.WriteLine(DateTime.Now.Second);
asAsync.DoOperation();
Console.WriteLine("After call to sync func using Async iface: {0}",
DateTime.Now.Second);
asAsync.DoOperationAsync().GetAwaiter().GetResult();
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Why should I declare a virtual destructor for an abstract class in C++?
I know it is a good practice to declare virtual destructors for base classes in C++, but is it always important to declare virtual destructors even for abstract classes that function as interfaces? Please provide some reasons and examples why.
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Safely turning a JSON string into an object
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The jQuery method is now deprecated. Use this method instead:
let jsonObject = JSON.parse(jsonString);
Original answer using deprecated jQuery functionality:
If you're using jQuery just use:
jQuery.parseJSON( jsonString );
It's exactly w...
What is a callback function?
... somewhere you can get to it
Execution comes back to where it was in [1]
Now suppose factorial took a really long time, because you're giving it huge numbers and it needs to run on some supercomputing cluster somwhere. Let's say you expect it to take 5 minutes to return your result. You could:
K...