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Lambda function in list comprehensions
...d calls it ten times.
The second one doesn't call the function. It creates 10 different lambda functions. It puts all of those in a list. To make it equivalent to the first you need:
[(lambda x: x*x)(x) for x in range(10)]
Or better yet:
[x*x for x in range(10)]
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About Python's built in sort() method
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Stephen Fuhry
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answered Oct 4 '09 at 20:53
Alex MartelliAlex...
Get the first N elements of an array?
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answered Sep 15 '10 at 17:25
corbachocorbacho
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Declaring an enum within a class
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answered Mar 23 '10 at 21:42
Peter AlexanderPeter Alexander
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Rounding float in Ruby
...; "2.35"
If you want to store it rounded, you can use
>> (2.3465*100).round / 100.0
=> 2.35
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SQLite string contains other string query
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answered Aug 17 '10 at 2:17
OMG PoniesOMG Ponies
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What is “incremental linking”?
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edited Jul 28 '10 at 3:16
answered Jul 28 '10 at 2:52
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Difference between Array and List in scala
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edited Apr 26 '10 at 11:26
answered Apr 26 '10 at 11:17
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What is the difference between lock and Mutex?
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answered Sep 17 '10 at 12:31
Darin DimitrovDarin Dimitrov
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Get size of folder or file
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edited Oct 28 '15 at 10:43
Aleksandr Dubinsky
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