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Generate a UUID on iOS from Swift
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You could also just use the NSUUID API:
let uuid = NSUUID()
If you want to get the string value back out, you can use uuid.UUIDString.
Note that NSUUID is available from iOS 6 and up.
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Android Writing Logs to text File
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Use slf4android lib.
It's simple implementation of slf4j api using android java.util.logging.*.
Features:
logging to file out of the box
logging to any other destination by LoggerConfiguration.configuration().addHandlerToLogger
shake your device to send logs with screenshot via ...
How do I invoke a Java method when given the method name as a string?
...invoked like this. There are also more possibilities (check the reflection api), but this is the simplest one:
import java.lang.reflect.InvocationTargetException;
import java.lang.reflect.Method;
import org.junit.Assert;
import org.junit.Test;
public class ReflectionTest {
private String met...
Is an HTTPS query string secure?
I am creating a secure web based API that uses HTTPS; however, if I allow the users to configure it (include sending password) using a query string will this also be secure or should I force it to be done via a POST?
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How do I measure request and response times at once using cURL?
...ders. I used this command to benchmark the response times of a third party API (supplying the bearer token in an Authorization header). Worked brilliantly.
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Android Fragment onClick button Method
... This causes the fragment to crash in my project which uses API 21. Any alternate fixes/suggestions?
– Darth Coder
Mar 10 '15 at 19:09
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Unit testing with Spring Security
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My goal is to build a Rest api without sessions. Perhaps with a refreshable token. While this did not answer my question it helped. Thanks
– Pomagranite
Aug 16 '17 at 14:12
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C++ Object Instantiation
...that takes an optional NULL pointer for example, or maybe it's an existing API that can't be changed.
– Mark Ransom
Nov 12 '15 at 17:25
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Sort a list by multiple attributes?
... to perhaps tell you how they want sorting done for some operation in your api by only have to give you a list and not coupling them to your back end implementation.
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What is the correct way to get a subarray in Scala?
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oh, of course, ArrayOps scala-lang.org/api/current/scala/collection/mutable/…, I'm dumb.
– nnythm
May 31 '12 at 9:43
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