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Directory does not exist. Parameter name: directoryVirtualPath
.../Admin/directives", "*.js")
.IncludeDirectory("~/Content/Admin/services", "*.js")
);
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LINQ: Distinct values
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Oh so by "larger type" you may mean I still want all properties in the result even though I only want to compare a few properties to determine distinctness?
– The Red Pea
Sep 20 '16 at 14:31
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Extract subset of key-value pairs from Python dictionary object?
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If you're using Python 3, and you only want keys in the new dict that actually exist in the original one, you can use the fact to view objects implement some set operations:
{k: bigdict[k] for k in bigdict.keys() & {'l', 'm', 'n'}}
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How do I force my .NET application to run as administrator?
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New Item... isn't an option on my Installer Service project. How would I go about adding the app manifest? I can add it to my main project but not it's installer.
– HackSlash
Mar 26 at 16:39
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How do I write LINQ's .Skip(1000).Take(100) in pure SQL?
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But this will first select all and then from that selection take only 10 right? Or will the first query/view have only 10 already?
– Tadej
Jan 29 '18 at 13:53
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What's the difference between %s and %d in Python string formatting?
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what do you call these %s, %d, etc?
– Chaine
May 19 '17 at 18:21
1
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How can I get a java.io.InputStream from a java.lang.String?
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You might be right. I originally made it a comment probably because it wasn't an actual answer to OP's question.
– Andres Riofrio
Jul 15 '13 at 18:52
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How to find keys of a hash?
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There is function in modern JavaScript (ECMAScript 5) called Object.keys performing this operation:
var obj = { "a" : 1, "b" : 2, "c" : 3};
alert(Object.keys(obj)); // will output ["a", "b", "c"]
Compatibility details can be found here.
On the Mozilla site there is also a sn...
Undoing a 'git push'
... highly dangerous if you are working in a shared repo. As a best practice, all commits pushed to a remote repo that is shared should be considered 'immutable'. Use 'git revert' instead: kernel.org/pub/software/scm/git/docs/…
– Saboosh
Jan 13 '12 at 20:47
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Sorting Python list based on the length of the string
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def lensort(list_1):
list_2=[];list_3=[]
for i in list_1:
list_2.append([i,len(i)])
list_2.sort(key = lambda x : x[1])
for i in list_2:
list_3.append(i[0])
return list_3
This works for me!
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