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Add comma to numbers every three digits

... 12 Answers 12 Active ...
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Reordering arrays

... 224 The syntax of Array.splice is: yourArray.splice(index, howmany, element1, /*.....,*/ elementX...
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Why does Math.round(0.49999999999999994) return 1?

....1 This is a specification bug, for precisely this one pathological case.2 Java 7 no longer mandates this broken implementation.3 The problem 0.5+0.49999999999999994 is exactly 1 in double precision: static void print(double d) { System.out.printf("%016x\n", Double.doubleToLongBits(d)); } ...
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Why does ~True result in -2?

... 240 int(True) is 1. 1 is: 00000001 and ~1 is: 11111110 Which is -2 in Two's complement1 1 ...
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Return first N key:value pairs from dict

... | edited Aug 21 '19 at 12:43 ofir_aghai 1,89811 gold badge2727 silver badges3030 bronze badges ...
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How does the extend() function work in jQuery?

...nd works, so I ran a little test: var a = {foo: 1, bar: 1}; var b = {foo: 2, baz: 2}; var c = {foo: 3}; var r = jQuery.extend(a,b,c); console.log("A: Foo=" + a.foo + " Bar=" + a.bar + " Baz=" + a.baz); console.log("B: Foo=" + b.foo + " Bar=" + b.bar + " Baz=" + b.baz); console.log("C: Foo=" + c.foo...
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Hash Map in Python

... 253 Python dictionary is a built-in type that supports key-value pairs. streetno = {"1": "Sachin ...
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combinations between two lists?

...e looking for - see the other answers. Suppose len(list1) >= len(list2). Then what you appear to want is to take all permutations of length len(list2) from list1 and match them with items from list2. In python: import itertools list1=['a','b','c'] list2=[1,2] [list(zip(x,list2)) for x in ite...
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Git 工具 - 子模块(submodule):一个仓库包含另一个仓库 - 开源 & Github -...

... /dev/null +++ b/DbConnector @@ -0,0 +1 @@ +Subproject commit c3f01dc8862123d317dd46284b05b6892c7b29bc 虽然 DbConnector 是工作目录中的一个子目录,但 Git 还是会将它视作一个子模块。当你不在那个目录中时,Git 并不会跟踪它的内容, 而是将它...
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Aggregate / summarize multiple variables per group (e.g. sum, mean)

... Where is this year() function from? You could also use the reshape2 package for this task: require(reshape2) df_melt <- melt(df1, id = c("date", "year", "month")) dcast(df_melt, year + month ~ variable, sum) # year month x1 x2 1 2000 1 -80.83405 -224.9540159 2 ...