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Get week of year in JavaScript like in PHP
...ek number as Moment.js ISO week number (tested over 50 years from 2000 to 2050).
Date.prototype.getWeekNumber = function(){
var d = new Date(Date.UTC(this.getFullYear(), this.getMonth(), this.getDate()));
var dayNum = d.getUTCDay() || 7;
d.setUTCDate(d.getUTCDate() + 4 - dayNum);
va...
How do I make an Android EditView 'Done' button and hide the keyboard when clicked?
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This is what ended up working for me. I decided to error with having actionDone in there as well, just in case some devices react differently.
– Jacksonkr
Mar 28 '16 at 16:10
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What does gcc's ffast-math actually do?
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@user: The magnitude of the error depends on the input data. It should be small relative to the result. For example, if x is smaller than 10, the error in Mystical's example will be down around 10^-10. But if x = 10e20, the error is likely to be many...
I can't install python-ldap
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Anything for windows users :( Same error, no solutions so far
– Shailen
Aug 13 '13 at 14:37
4
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How to check version of a CocoaPods framework
... can open it but if we try to save, it will generate ASCII values and give errors. champlintechnologiesllc.com/20_cocoapods_xcode
– Nagarjun
Nov 27 '19 at 0:29
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How do I add a placeholder on a CharField in Django?
...t specify the field (e.g. for some dynamic method), you can use this:
def __init__(self, *args, **kwargs):
super(MyForm, self).__init__(*args, **kwargs)
self.fields['email'].widget.attrs['placeholder'] = self.fields['email'].label or 'email@address.nl'
It also allows the placeholder to de...
How can I get current date in Android?
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There are errors, new Date() is asking for arguments, and you are initializing the DateFormat with SimpleDateFormat, also not valid
– Chatar Veer Suthar
Dec 28 '11 at 11:18
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Convert nested Python dict to object?
...']
The alternative (original answer contents) is:
class Struct:
def __init__(self, **entries):
self.__dict__.update(entries)
Then, you can use:
>>> args = {'a': 1, 'b': 2}
>>> s = Struct(**args)
>>> s
<__main__.Struct instance at 0x01D6A738>
>>...
What is the most efficient way of finding all the factors of a number in Python?
...om functools import reduce
def factors(n):
return set(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
This will return all of the factors, very quickly, of a number n.
Why square root as the upper limit?
sqrt(x) * sqrt(x) = x. So if t...
Check whether a cell contains a substring
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got an error using , instead of ;. After changing the provided formula to =ISNUMBER(SEARCH("Some Text"; A3)) it worked. Thanks!
– renatov
Apr 22 '15 at 19:18
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