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How do I initialize the base (super) class?
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pass
class Y(X):
def __init__(self):
super(Y, self).__init__(123)
def doit(self, foo):
return super(Y, self).doit(foo)
Because python knows about old- and new-style classes, there are different ways to invoke a base method, which is why you've found multiple ways of doing so.
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Why is \r a newline for Vim?
...lacement pattern.
– dlamblin
Dec 4 '12 at 17:09
3
@dlamblin Yup! See my answer :)
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Ignore Xcode warnings when using Cocoapods
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answered Nov 3 '12 at 12:11
alloyalloy
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SQLite in Android How to update a specific row
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edited Dec 16 '15 at 12:53
akshay7692
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answered M...
Select second last element with css
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answered Mar 24 '11 at 12:08
Frosty ZFrosty Z
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Import a module from a relative path
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Peter Mortensen
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answered May 23 '11 at 14:00
sorinsorin
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PEP 8, why no spaces around '=' in keyword argument or a default parameter value?
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answered Jan 13 '12 at 15:40
fortranfortran
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Performance - Date.now() vs Date.getTime()
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answered Sep 20 '12 at 17:04
PointyPointy
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How to compile tests with SBT without running them
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edited Dec 12 '12 at 19:57
Dave Clemmer
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How does Spring Data JPA differ from Hibernate for large projects?
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answered Oct 9 '12 at 18:56
sbzoomsbzoom
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