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How to deal with floating point number precision in JavaScript?
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42 Answers
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What is the difference between shallow copy, deepcopy and normal assignment operation?
... the
original.
Here's a little demonstration:
import copy
a = [1, 2, 3]
b = [4, 5, 6]
c = [a, b]
Using normal assignment operatings to copy:
d = c
print id(c) == id(d) # True - d is the same object as c
print id(c[0]) == id(d[0]) # True - d[0] is the same object as c[0]
Us...
Upgrading PHP in XAMPP for Windows?
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128
Take a backup of your htdocs and data folder (subfolder of MySQL folder), reinstall upgraded ve...
Any gotchas using unicode_literals in Python 2.6?
We've already gotten our code base running under Python 2.6. In order to prepare for Python 3.0, we've started adding:
6 A...
Center a map in d3 given a geoJSON object
... = d3.geo.centroid(json)
var scale = 150;
var offset = [width/2, height/2];
var projection = d3.geo.mercator().scale(scale).center(center)
.translate(offset);
// create the path
var path = d3.geo.path().projection(projection);
// using the path determ...
Reshaping data.frame from wide to long format
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edited Oct 21 '19 at 10:33
Jaap
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Android Center text on canvas
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Try the following:
int xPos = (canvas.getWidth() / 2);
int yPos = (int) ((canvas.getHeight() / 2) - ((textPaint.descent() + textPaint.ascent()) / 2)) ;
//((textPaint.descent() + textPaint.ascent()) / 2) is the distance from the baseline to the center.
canvas.drawText("He...
The tilde operator in Python
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204
It is a unary operator (taking a single argument) that is borrowed from C, where all data type...
How do I get indices of N maximum values in a NumPy array?
...mplest I've been able to come up with is:
In [1]: import numpy as np
In [2]: arr = np.array([1, 3, 2, 4, 5])
In [3]: arr.argsort()[-3:][::-1]
Out[3]: array([4, 3, 1])
This involves a complete sort of the array. I wonder if numpy provides a built-in way to do a partial sort; so far I haven't bee...
Is it possible to have multiple statements in a python lambda expression?
...found in the heapq module.
>>> import heapq
>>> l = [5,2,6,8,3,5]
>>> heapq.nsmallest(l, 2)
[2, 3]
So just use:
map(lambda x: heapq.nsmallest(x,2)[1], list_of_lists)
It's also usually considered clearer to use a list comprehension, which avoids the lambda altogethe...
