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How to get the size of a string in Python?
For example, I get a string:
5 Answers
5
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Case insensitive string compare in LINQ-to-SQL
...ad that it's unwise to use ToUpper and ToLower to perform case-insensitive string comparisons, but I see no alternative when it comes to LINQ-to-SQL. The ignoreCase and CompareOptions arguments of String.Compare are ignored by LINQ-to-SQL (if you're using a case-sensitive database, you get a case-se...
Make a phone call programmatically
...lue doesn't include the scheme tel://
Your code should look like this:
NSString *phoneNumber = [@"tel://" stringByAppendingString:mymobileNO.titleLabel.text];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
...
MVC4 StyleBundle not resolving images
...Context context, BundleResponse response)
{
response.Content = String.Empty;
Regex pattern = new Regex(@"url\s*\(\s*([""']?)([^:)]+)\1\s*\)", RegexOptions.IgnoreCase);
// open each of the files
foreach (FileInfo cssFileInfo in response.Files)
{
...
Remove or adapt border of frame of legend using matplotlib
...)
legend.get_frame().set_facecolor('none')
Warning, you want 'none' (the string). None means the default color instead.
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How to convert string representation of list to a list?
I was wondering what the simplest way is to convert a string list like the following to a list :
15 Answers
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Javascript fuzzy search that makes sense
...mong other things, found this:
http://www.joyofdata.de/blog/comparison-of-string-distance-algorithms/
This mentions a number of "string distance" measures. Three which looked particularly relevant to your requirement, would be:
Longest Common Substring distance: Minimum number of symbols that ha...
How can I read input from the console using the Scanner class in Java?
...rintln("Enter your username: ");
Scanner scanner = new Scanner(System.in);
String username = scanner.nextLine();
System.out.println("Your username is " + username);
You could also use next(String pattern) if you want more control over the input, or just validate the username variable.
You'll find...
Object initialization syntax
...gives you a similar syntax, but keeps things immutable:
type Person(name:string, ?birthDate) =
member x.Name = name
member x.BirthDate = defaultArg birthDate System.DateTime.MinValue
Now we can write:
let p1 = new Person(name="John", birthDate=DateTime.Now)
let p2 = new Person(name="John")
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TypeScript Objects as Dictionary types as in C#
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In newer versions of typescript you can use:
type Customers = Record<string, Customer>
In older versions you can use:
var map: { [email: string]: Customer; } = { };
map['foo@gmail.com'] = new Customer(); // OK
map[14] = new Customer(); // Not OK, 14 is not a string
map['bar@hotmail.com']...
