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How to get the size of a string in Python?

For example, I get a string: 5 Answers 5 ...
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Case insensitive string compare in LINQ-to-SQL

...ad that it's unwise to use ToUpper and ToLower to perform case-insensitive string comparisons, but I see no alternative when it comes to LINQ-to-SQL. The ignoreCase and CompareOptions arguments of String.Compare are ignored by LINQ-to-SQL (if you're using a case-sensitive database, you get a case-se...
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Make a phone call programmatically

...lue doesn't include the scheme tel:// Your code should look like this: NSString *phoneNumber = [@"tel://" stringByAppendingString:mymobileNO.titleLabel.text]; [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]]; ...
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MVC4 StyleBundle not resolving images

...Context context, BundleResponse response) { response.Content = String.Empty; Regex pattern = new Regex(@"url\s*\(\s*([""']?)([^:)]+)\1\s*\)", RegexOptions.IgnoreCase); // open each of the files foreach (FileInfo cssFileInfo in response.Files) { ...
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Remove or adapt border of frame of legend using matplotlib

...) legend.get_frame().set_facecolor('none') Warning, you want 'none' (the string). None means the default color instead. share | improve this answer | follow ...
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How to convert string representation of list to a list?

I was wondering what the simplest way is to convert a string list like the following to a list : 15 Answers ...
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Javascript fuzzy search that makes sense

...mong other things, found this: http://www.joyofdata.de/blog/comparison-of-string-distance-algorithms/ This mentions a number of "string distance" measures. Three which looked particularly relevant to your requirement, would be: Longest Common Substring distance: Minimum number of symbols that ha...
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How can I read input from the console using the Scanner class in Java?

...rintln("Enter your username: "); Scanner scanner = new Scanner(System.in); String username = scanner.nextLine(); System.out.println("Your username is " + username); You could also use next(String pattern) if you want more control over the input, or just validate the username variable. You'll find...
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Object initialization syntax

...gives you a similar syntax, but keeps things immutable: type Person(name:string, ?birthDate) = member x.Name = name member x.BirthDate = defaultArg birthDate System.DateTime.MinValue Now we can write: let p1 = new Person(name="John", birthDate=DateTime.Now) let p2 = new Person(name="John") ...
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TypeScript Objects as Dictionary types as in C#

... In newer versions of typescript you can use: type Customers = Record<string, Customer> In older versions you can use: var map: { [email: string]: Customer; } = { }; map['foo@gmail.com'] = new Customer(); // OK map[14] = new Customer(); // Not OK, 14 is not a string map['bar@hotmail.com']...