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Can I invoke an instance method on a Ruby module without including it?
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If a method on a module is turned into a module function you can simply call it off of Mods as if it had been declared as
module Mods
def self.foo
puts "Mods.foo(self)"
end
end
The module_function approach below will avoid breaking any classes which include all of Mods.
module Mods
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“unrecognized import path” with go get
I'm trying to install a web.go , but running go get github.com/hoisie/web returns
9 Answers
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Why use the 'ref' keyword when passing an object?
...) {
obj = new Object();
}
public void Method2(object obj) {
obj = _privateObject;
}
The methods above does not modifies the original object.
A little modification of your example
using System;
class Program
{
static void Main(string[] args)
{
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Visual Studio Clicking Find Results Opens Code in Wrong Window
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Thanks. Works in VS2015 also
– RandallTo
Nov 24 '15 at 17:29
This solution usually fixes it for me q...
Objective-C declared @property attributes (nonatomic, copy, strong, weak)
... retaining the copy.
Assign
Assign is somewhat the opposite to copy. When calling the getter of an assign property, it returns a reference to the actual data. Typically you use this attribute when you have a property of primitive type (float, int, BOOL...)
Retain
retain is required when the attribut...
What does O(log n) mean exactly?
...g that the size of the input affects the growth of the algorithm proportionally...and the same goes for, for example, quadratic time O(n2) etc..even algorithms, such as permutation generators, with O(n!) times, that grow by factorials.
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How do I write a “tab” in Python?
Let's say I have a file. How do I write "hello" TAB "alex"?
6 Answers
6
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Change the selected value of a drop-down list with jQuery
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jQuery's documentation states:
[jQuery.val] checks, or selects, all the radio buttons, checkboxes, and select options that match the set of values.
This behavior is in jQuery versions 1.2 and above.
You most likely want this:
$("._statusDDL").val('2');
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What is this crazy C++11 syntax ==> struct : bar {} foo {};?
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First, we'll take a bog-standard abstract UDT (User-Defined Type):
struct foo { virtual void f() = 0; }; // normal abstract type
foo obj;
// error: cannot declare variable 'obj' to be of abstract type 'foo'
Let's also reca...
How to get the Power of some Integer in Swift language?
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I really like this solution, but with Swift 3 it does not work. Any idea how to make it work?
– Vanya
Sep 19 '16 at 18:51
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