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What is a patch in git version control?

...ges you want to communicate and apply to another repo) (picture from the 2008 blog post "Bioruby with git: how would that work?", published by Jan AERTS) See also Contributing to Rails with Git as another concrete example. Nowadays, the GitHub pull request makes it really easy to apply patches o...
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How can I add numbers in a Bash script?

... For integers: Use arithmetic expansion: $((EXPR)) num=$((num1 + num2)) num=$(($num1 + $num2)) # Also works num=$((num1 + 2 + 3)) # ... num=$[num1+num2] # Old, deprecated arithmetic expression syntax Using the external expr utility. Note that this is only needed for ...
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What Ruby IDE do you prefer? [closed]

... 25 Answers 25 Active ...
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How can I get the full object in Node.js's console.log(), rather than '[Object]'?

... | edited Sep 4 '18 at 18:28 Ikbel 6,07422 gold badges2828 silver badges3939 bronze badges answered May ...
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How can I parse a time string containing milliseconds in it with python?

... 327 Python 2.6 added a new strftime/strptime macro %f, which does microseconds. Not sure if this i...
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Mockito. Verify method arguments

... | edited Feb 19 '17 at 21:00 Nikunj Undhad 22222 silver badges66 bronze badges answered Aug 19 '15 at...
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Error:(1, 0) Plugin with id 'com.android.application' not found

... my first attempt at Android Studio. I installed 0.8.0 and updated to 0.8.2. As soon as a project is created I get the error message: ...
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Get exception description and stack trace which caused an exception, all as a string

... ianace 1,60722 gold badges1717 silver badges3131 bronze badges answered Dec 30 '10 at 17:05 kindallkindall ...
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Define a lambda expression that raises an Exception

... however allow you to conditionally raise exceptions, e.g.: y = lambda x: 2*x if x < 10 else raise_(Exception('foobar')) Alternatively you can raise an exception without defining a named function. All you need is a strong stomach (and 2.x for the given code): type(lambda:0)(type((lambda:0)....
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Parse DateTime string in JavaScript

....1979"; var dateParts = strDate.split("."); var date = new Date(dateParts[2], (dateParts[1] - 1), dateParts[0]); share | improve this answer | follow | ...