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Is there an MD5 Fixed Point where md5(x) == x?
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Since an MD5 sum is 128 bits long, any fixed point would necessarily also have to be 128 bits long. Assuming that the MD5 sum of any string is uniformly distributed over all possible sums, then the probability that any given 12...
Choose between ExecutorService's submit and ExecutorService's execute
How should I choose between ExecutorService's submit or execute , if the returned value is not my concern?
7 Answers
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为什么我们程序员写不出好代码? - 杂谈 - 清泛网 - 专注C/C++及内核技术
...目管理的太细,因为他们一旦有新的观点,代码就会大片修改。
8.技术过硬但有些强势的程序员
程序员往往都是因为过硬的技术才被公司赏识,而不是人际交往。但不能每次出现问题都责怪穿西装不自在或销售人员过于热情,...
Apache .htaccess 禁止访问某目录方法 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...asswords lily(htpasswd d:/passwords groups)为编辑组添加两个用户
修改.htaccess:
AuthType Basic
AuthName "By Invitation Only"
AuthUserFile d:/passwords
AuthGroupFile d:/groups
Require group admin editer
当然也可以使用Require valid-user指令允许密码文件中的所有用...
plupload图片上传插件的使用 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...当然每个插件在使用过程中未必跟业务完全耦合,就看你修改插件让其符合业务...plupload算是一个好东西(用过的人都知道),用起来不好不坏的,当然每个插件在使用过程中未必跟业务完全耦合,就看你修改插件让其符合业务...
Java's L number (long) specification
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Late entry: removing potential sources of ambiguity is always good, and I don't disagree... but I believe if you find yourself confusing 1 with l and 0 with O (and so on), your priority is to set the font right (if you can), then worry about making sure you do...
海量数据相似度计算之simhash和海明距离 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
...的 “4 -4 -4 4 -4 4”,“51区”的 “ 5 -5 5 -5 5 5”, 把每一位进行累加, “4+5 -4+-5 -4+5 4+-5 -4+5 4+5” ==》 “9 -9 1 -1 1 9”。这里作为示例只算了两个单词的,真实计算需要把所有单词的序列串累加。
5、降维,把4步算出来的 “9 ...
How to split last commit into two in Git
...dex.
$ git add -p myfile
diff --git a/myfile b/myfile
index 93db4cb..2f113ce 100644
--- a/myfile
+++ b/myfile
@@ -1,3 +1,5 @@
+1
something
something else
something again
+2
Stage this hunk [y,n,a,d,/,s,e,?]? s # split this section into two!
Split into 2 hunks.
@@ -1,3 +1,4 @@
+1
something
s...
How to find and return a duplicate value in array
...s beautiful one liner code. And works perfectly fine unless you need to process huge data set.
Looking for faster solution? Here you go!
def find_one_using_hash_map(array)
map = {}
dup = nil
array.each do |v|
map[v] = (map[v] || 0 ) + 1
if map[v] > 1
dup = v
break
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mfc里面的140种颜色宏 - C/C++ - 清泛网 - 专注C/C++及内核技术
...R_BLACK RGB( 0, 0, 0) // 纯黑
完整.h文件下载:ColorDef.zip
mfc 颜色宏
