大约有 41,200 项符合查询结果（耗时：0.0536秒） [XML]
Swift 编程语言入门教程 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...教程，分享给大家
原文地址：http://gashero.iteye.com/blog/2075324
目录
1 简介
2 Swift入门
3 简单值
4 控制流
5 函数与闭包
6 对象与类
7 枚举与结构
1 简介
今天凌晨Apple刚刚发布了Swift编程语言，本文从其发布...
How to get execution time in rails console?
...
3 Answers
3
Active
...
Convert a PHP object to an associative array
...
32 Answers
32
Active
...
Finding the index of elements based on a condition using python list comprehension
... of a list.
>>> import numpy
>>> a = numpy.array([1, 2, 3, 1, 2, 3])
>>> a
array([1, 2, 3, 1, 2, 3])
>>> numpy.where(a > 2)
(array([2, 5]),)
>>> a > 2
array([False, False, True, False, False, True], dtype=bool)
>>> a[numpy.where(a > 2...
iPhone Simulator location
...
143
Simulator: ~/Library/Application Support/iPhone Simulator/
You can browse simulator files from ...
How to extend an existing JavaScript array with another array, without creating a new array
...
1553
The .push method can take multiple arguments. You can use the spread operator to pass all the el...
What is the best regular expression to check if a string is a valid URL?
... wrote my URL (actually IRI, internationalized) pattern to comply with RFC 3987 (http://www.faqs.org/rfcs/rfc3987.html). These are in PCRE syntax.
For absolute IRIs (internationalized):
/^[a-z](?:[-a-z0-9\+\.])*:(?:\/\/(?:(?:%[0-9a-f][0-9a-f]|[-a-z0-9\._~\x{A0}-\x{D7FF}\x{F900}-\x{FDCF}\x{FDF0}-\x...
Getting parts of a URL (Regex)
...
153
A single regex to parse and breakup a
full URL including query parameters
and anchors e.g...
How to make a flat list out of list of lists?
...e the timeit module in the standard library:
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in l for item in sublist]'
10000 loops, best of 3: 143 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(l, [])'
1000 loops, best of 3: 969 usec per loo...
How to compare two floating point numbers in Bash?
...s in scientific format, provided a capital letter E is employed, e.g. num1=3.44E6
share
|
improve this answer
|
follow
|
...