大约有 41,100 项符合查询结果（耗时：0.0505秒） [XML]
Swift 编程语言入门教程 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...教程，分享给大家
原文地址：http://gashero.iteye.com/blog/2075324
目录
1 简介
2 Swift入门
3 简单值
4 控制流
5 函数与闭包
6 对象与类
7 枚举与结构
1 简介
今天凌晨Apple刚刚发布了Swift编程语言，本文从其发布...
How to get execution time in rails console?
...
3 Answers
3
Active
...
Convert a PHP object to an associative array
...
32 Answers
32
Active
...
Finding the index of elements based on a condition using python list comprehension
... of a list.
>>> import numpy
>>> a = numpy.array([1, 2, 3, 1, 2, 3])
>>> a
array([1, 2, 3, 1, 2, 3])
>>> numpy.where(a > 2)
(array([2, 5]),)
>>> a > 2
array([False, False, True, False, False, True], dtype=bool)
>>> a[numpy.where(a > 2...
What is the best regular expression to check if a string is a valid URL?
... wrote my URL (actually IRI, internationalized) pattern to comply with RFC 3987 (http://www.faqs.org/rfcs/rfc3987.html). These are in PCRE syntax.
For absolute IRIs (internationalized):
/^[a-z](?:[-a-z0-9\+\.])*:(?:\/\/(?:(?:%[0-9a-f][0-9a-f]|[-a-z0-9\._~\x{A0}-\x{D7FF}\x{F900}-\x{FDCF}\x{FDF0}-\x...
How to extend an existing JavaScript array with another array, without creating a new array
...
1553
The .push method can take multiple arguments. You can use the spread operator to pass all the el...
iPhone Simulator location
...
143
Simulator: ~/Library/Application Support/iPhone Simulator/
You can browse simulator files from ...
Getting parts of a URL (Regex)
...
153
A single regex to parse and breakup a
full URL including query parameters
and anchors e.g...
How to make a flat list out of list of lists?
...e the timeit module in the standard library:
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in l for item in sublist]'
10000 loops, best of 3: 143 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(l, [])'
1000 loops, best of 3: 969 usec per loo...
How to compare two floating point numbers in Bash?
...s in scientific format, provided a capital letter E is employed, e.g. num1=3.44E6
share
|
improve this answer
|
follow
|
...