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Do the JSON keys have to be surrounded by quotes?
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You are correct to use strings as the key. Here is an excerpt from RFC 4627 - The application/json Media Type for JavaScript Object Notation (JSON)
2.2. Objects
An object structure is represented as a pair of curly brackets
surrounding...
Loop inside React JSX
...this with a ul (unordered list). <ul> {objects.map((object:string,i:number)=>{ return <li>{object}</li> })} </ul> using TypeScript
– Roberto C Navarro
Sep 28 '15 at 20:10
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GIT: Checkout to a specific folder
...important. The exported name is literally just prefixed with the specified string.
If you want to export a certain directory, there are some tricks involved. The command only takes files, not directories. To apply it to directories, use the 'find' command and pipe the output to git.
find dirname ...
Why covariance and contravariance do not support value type
...he values. References all look the same - so you can use an IEnumerable<string> as an IEnumerable<object> without any change in representation; the native code itself doesn't need to know what you're doing with the values at all, so long as the infrastructure has guaranteed that it will ...
What is the difference between Directory.EnumerateFiles vs Directory.GetFiles?
...merable which can be lazily evaluated somewhat, whereas GetFiles returns a string[] which has to be fully populated before it can return.
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bash: shortest way to get n-th column of output
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But then I need to type an extra space. That's too exhausting :)
– StackedCrooked
Jun 30 '18 at 9:32
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How to present a simple alert message in java?
...ity" you can always wrap your code in a short method:
private void msgbox(String s){
JOptionPane.showMessageDialog(null, s);
}
and the usage:
msgbox("don't touch that!");
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Create a string of variable length, filled with a repeated character
...as been asked by someone else in it's Java form here: Java - Create a new String instance with specified length and filled with specific character. Best solution?
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Reading in a JSON File Using Swift
....mutableLeaves)
if let jsonResult = jsonResult as? Dictionary<String, AnyObject>, let person = jsonResult["person"] as? [Any] {
// do stuff
}
} catch {
// handle error
}
}
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Loading a properties file from Java package
...e directory which represents the package the class is in.
Using java.lang.String.class.getResource("foo.txt") would search for the (inexistent) file /java/lang/String/foo.txt on the classpath.
Using an absolute path (one that starts with '/') means that the current package is ignored.
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