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How to get the next auto-increment id in mysql
...om your SQL query.
Or
You can also use mysql_insert_id() to get it using PHP.
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Get JSON object from URL
...//paragonie.com/blog/2017/10/certainty-automated-cacert-pem-management-for-php-software
// in most cases, you should set it to true
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
cu...
VM 磁盘空间扩容引起的一些问题 - 更多技术 - 清泛网 - 专注C/C++及内核技术
VM 磁盘空间扩容引起的一些问题TOP如下存储分区如下ESX1下挂载情况如下图ESX2下挂载情况如下图现在有个需求，lun60的空间偏大，缩小为1T，LUN80的空间偏小，扩大为1.5T先...TOP 如下
存储分区如下
ESX1下挂载情况如下图
...
为什么大数据也不能帮你摆脱单身狗的命运？ - 资讯 - 清泛网 - 专注C/C++及内核技术
...几个选。而这些结果基于也许就几十个，一般你回答几个问题，或者你产生的一些行为。基本数据：年龄、身高…户口所在地、毕业学校、工作单位、家庭状况。一些网站最厉害的问你100个问题，什么喜欢的颜色，食物，运动，...
How to post data to specific URL using WebClient in C#
...)
so here is the solution:
string URI = "http://www.myurl.com/post.php";
string myParameters = "param1=value1&param2=value2&param3=value3";
using (WebClient wc = new WebClient())
{
wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
string HtmlRe...
Difference between and
... get submitted.
Sample HTML form (index.html):
<form action="checkout.php" method="POST">
<!-- this won't get submitted despite being named -->
<input type="button" name="button1" value="a button">
<!-- this one does; so the input's TYPE is important! -->
<inpu...
What is SQL injection? [duplicate]
...ta or even changing data that they shouldn't be allowed to do.
Example in PHP:
$password = $_POST['password'];
$id = $_POST['id'];
$sql = "UPDATE Accounts SET PASSWORD = '$password' WHERE account_id = $id";
Now suppose the attacker sets the POST request parameters to "password=xyzzy" and "id=acc...
Memcached下一站：HandlerSocket！ - 更多技术 - 清泛网 - 专注C/C++及内核技术
...形中让Memcached成为故障的根源：
Memcached数据一致性的问题：当MySQL数据变化后，如果不能及时有效的清理掉过期的数据，就会造成数据不一致。这在强调即时性的Web2.0时代，不可取。
Memcached崩溃后的雪崩效应：作为缓存的Memc...
C语言面试那些事儿──一道指针与数组问题 - C/C++ - 清泛网 - 专注C/C++及内核技术
C语言面试那些事儿──一道指针与数组问题首先看如下代码：int main(int argc, char** argv){ int a[5] = {1,2,3,4,5}; int* ptr = (int*)(&a + 1); ...首先看如下代码：
int main(int argc, char** argv)
{
int a[5] = {1,2,3,4,5};
int* ptr = (int*)(&a + 1);
...
Picture Control(图片控件)中静态显示位图，解决位图不显示的问题 - C/C++ ...
...cture Control(图片控件)中静态显示位图，解决位图不显示的问题Picture Control(图片控件)中静态显示位图，如果出现不显示的问题，可以再手动调一下ShowWindow方法，一般就OK了。Picture Control(图片控件)中静态显示位图，代码如下：
v...