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How do DATETIME values work in SQLite?
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select * from table where creation between a and b;
– koem
Jun 21 '13 at 4:07
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Why is there no multiple inheritance in Java, but implementing multiple interfaces is allowed?
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@curiousguy: If a framework provides that casting an object reference to a base-type reference will be identity preserving, then every object instance must have exactly one implementation of any base-class method. If ToyotaCar and HybridCar both derived from Car and...
Why does int i = 1024 * 1024 * 1024 * 1024 compile without error?
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Right. Assigning an int to a long includes an implicit cast. But the value can never exist as the int in the first place to get casted :)
– Cruncher
Jul 11 '14 at 18:14
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Is there more to an interface than having the correct methods
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How did this get selected as the answer? It's a brief description of why polymorphism is useful, but as the poster above said, I would expect a better explanation of multiple interfaces and even more importantly when it is appropriate to use ...
How does virtual inheritance solve the “diamond” (multiple inheritance) ambiguity?
...nheritance diagrams to show the derived classes below the bases. (see "downcast", "upcast")
– peterh - Reinstate Monica
Jul 8 '16 at 20:27
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Why would finding a type's initializer throw a NullReferenceException?
...found at least 3 workaround approaches for fixing the problem:
Simply by casting the Type to _Type inside the Main method:
var cctor = ((_Type)typeof(Test)).TypeInitializer;
Or making sure that approach 1 was used previously inside the method:
var warmUp = ((_Type)typeof(Test)).TypeInitializer;...
Why doesn't Java offer operator overloading?
...and one double. There is even the whole pointer arithmetic domain (without casting, you can add to a pointer an integer, but you cannot add two pointers...).
In Java, there is no pointer arithmetic, but someone still found string concatenation without the + operator would be ridiculous enough to ju...
vs in Generics
...of the generic class, interface or method. The implication is that you can cast the type/interface/method to an equivalent with a super-type of T.
E.g. ICovariant<out Dog> can be cast to ICovariant<Animal>.
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JavaScript plus sign in front of function expression
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Subsidiary to @TJCrowder's answer, + is usually used to force numerical casting of a value as this SO answer explains. In this instance it is called the 'unary plus operator' (for ease of googling).
var num = +variant;
So in front of a function it can be a way to force the function's result to...
Adding two Java 8 streams, or an extra element to a stream
...type of Something<? extends T>, not the other way, so it couldn't be cast) Additional .map(identity()) cast <? extends T> to <T>. It happens thanks to mix of java 8 'target types' of method arguments and return types and signature of map() method. Actually it is Function.<T>i...