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Getting key with maximum value in dictionary?
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You can use operator.itemgetter for that:
import operator
stats = {'a':1000, 'b':3000, 'c': 100}
max(stats.iteritems(), key=operator.itemgetter(1))[0]
And instead of building a new list in memory use stats.iteritems(). The key parameter to the max() function is a function that computes a key t...
How to validate an email address in PHP
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How to extract text from a string using sed?
...ing line), use a substitution.
sed -n 's/.*\([0-9][0-9]*G[0-9][0-9]*\).*/\1/p'
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How do I replace NA values with zeros in an R dataframe?
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21 Answers
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Convert floats to ints in Pandas?
...mns=['a'])
df.a = df.a.astype(float)
df
Out[33]:
a
0 0.0000000
1 1.0000000
2 2.0000000
3 3.0000000
4 4.0000000
pd.options.display.float_format = '{:,.0f}'.format
df
Out[35]:
a
0 0
1 1
2 2
3 3
4 4
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How is “int* ptr = int()” value initialization not illegal?
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int() is a constant expression with a value of 0, so it's a valid way of producing a null poin...
pandas: filter rows of DataFrame with operator chaining
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14 Answers
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How do I upgrade my ruby 1.9.2-p0 to the latest patch level using rvm?
My current version of ruby is ruby 1.9.2p0 (2010-08-18 revision 29036) [x86_64-darwin10.5.0] but I want to update it to the latest patch level using rvm. How can I do this?
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Ruby on Rails and Rake problems: uninitialized constant Rake::DSL
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19 Answers
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