大约有 15,000 项符合查询结果（耗时：0.0311秒） [XML]
How can I list ALL DNS records?
...
When you query for ANY you will get a list of all records at that level but not below.
# try this
dig google.com any
This may return A records, TXT records, NS records, MX records, etc if the domain name is exactly "google.com". However, it will not retu...
Test whether string is a valid integer
I'm trying to do something common enough: Parse user input in a shell script. If the user provided a valid integer, the script does one thing, and if not valid, it does something else. Trouble is, I haven't found an easy (and reasonably elegant) way of doing this - I don't want to have to pick it ap...
Run all SQL files in a directory
I have a number of .sql files which I have to run in order to apply changes made by other developers on an SQL Server 2005 database.
The files are named according to the following pattern:
...
Change multiple files
The following command is correctly changing the contents of 2 files.
9 Answers
9
...
Algorithm to generate a crossword
Given a list of words, how would you go about arranging them into a crossword grid?
13 Answers
...
常用Linux命令详解（持续更新） - 更多技术 - 清泛网 - 专注C/C++及内核技术
...日常工作中经常会用到的一些Linux命令进行一下详解。logout,shutdown,reboot,useradd,passwd,ls,ll,cd,mkdir,vi,cp,rm,mv,chmod,chown,find,grep,tail,tar,gzip,fdisk,kill,netstat等。一、注销，关机，重启，新建用户、删除用户
1. 注销系统的命令
logout 、exit
...
RegEx to extract all matches from string using RegExp.exec
I'm trying to parse the following kind of string:
17 Answers
17
...
Change a column type from Date to DateTime during ROR migration
I need to change my column type from date to datetime for an app I am making. I don't care about the data as its still being developed.
...
What does the `#` operator mean in Scala?
I see this code in this blog: Type-Level Programming in Scala :
4 Answers
4
...
How to replace strings containing slashes with sed?
... way would be to use a different delimiter in your search/replace lines, e.g.:
s:?page=one&:pageone:g
You can use any character as a delimiter that's not part of either string. Or, you could escape it with a backslash:
s/\//foo/
Which would replace / with foo. You'd want to use the escaped...