大约有 35,450 项符合查询结果(耗时:0.0409秒) [XML]
Redirecting to URL in Flask
...oute('/')
def hello():
return redirect("http://www.example.com", code=302)
if __name__ == '__main__':
# Bind to PORT if defined, otherwise default to 5000.
port = int(os.environ.get('PORT', 5000))
app.run(host='0.0.0.0', port=port)
See the documentation on flask docs. The default ...
How do I create a list of random numbers without duplicates?
I tried using random.randint(0, 100) , but some numbers were the same. Is there a method/module to create a list unique random numbers?
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Why does Decimal.Divide(int, int) work, but not (int / int)?
How come dividing two 32 bit int numbers as ( int / int ) returns to me 0 , but if I use Decimal.Divide() I get the correct answer? I'm by no means a c# guy.
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Appropriate datatype for holding percent values?
What is the best datatype for holding percent values ranging from 0.00% to 100.00%?
5 Answers
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Prevent flicker on webkit-transition of webkit-transform [duplicate]
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answered Oct 13 '10 at 8:21
rpittingrpitting
3,21511 gold badge1616 silver badges1010 bronze badges
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Is this object-lifetime-extending-closure a C# compiler bug?
...n into some extremely curious code-gen on the part of the C# compiler (4.0 if that matters).
2 Answers
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Using .NET, how can you find the mime type of a file based on the file signature not the extension
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answered Sep 12 '08 at 9:44
Steve MorganSteve Morgan
12.4k22 gold badges3838 silver badges4949 bronze badges
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C++: Rounding up to the nearest multiple of a number
...ger math.
int roundUp(int numToRound, int multiple)
{
if (multiple == 0)
return numToRound;
int remainder = numToRound % multiple;
if (remainder == 0)
return numToRound;
return numToRound + multiple - remainder;
}
Edit: Here's a version that works with negative n...
How do you get the width and height of a multi-dimensional array?
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answered Nov 23 '10 at 19:52
Reed CopseyReed Copsey
509k6868 gold badges10671067 silver badges13241324 bronze badges
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Decreasing for loops in Python impossible?
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220
for n in range(6,0,-1):
print n
# prints [6, 5, 4, 3, 2, 1]
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