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Why is === faster than == in PHP?
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I believe it's actually that the 2 operands point to the same area of memory for complex types but meder's answer encompasses that
– Basic
Aug 24 '10 at 19:21
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How to set my phpmyadmin user session to not time out so quickly? [duplicate]
...ger than 1800.
Note:
Always keep on mind that a short cookie lifetime is all well and good for the development server. So do not do this on your production server.
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如何编写一个独立的 PHP 扩展（译） - 更多技术 - 清泛网 - 专注C/C++及内核技术
如何编写一个独立的 PHP 扩展（译）how-to-create-a-php-extension本文翻译自 PHP 源码中的 README.SELF-CONTAINED-EXTENSIONS。文中标记了注的内容均为自己添加。内容有点老，也挺啰嗦，没讲什么深入的...本文翻译自 PHP 源码中的 README.SELF-CONTAI...
Foreign keys in mongo?
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UPD. I'am using PHP as a programming language, how can I use mongoid, if it is written in Ruby?
– Mark Pegasov
Jun 13 '11 at 17:54
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json_encode sparse PHP array as JSON array, not JSON object
...at is, if its keys are 0, 1, 2, 3, ...
You can reindex your array sequentially using the array_values function to get the behaviour you want. For example, the code below works successfully in your use case:
echo json_encode(array_values($input)).
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“date(): It is not safe to rely on the system's timezone settings…”
I got this error when I requested to update the PHP version from 5.2.17 to PHP 5.3.21 on the server.
24 Answers
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JavaScript isset() equivalent
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I generally use the typeof operator:
if (typeof obj.foo !== 'undefined') {
// your code here
}
It will return "undefined" either if the property doesn't exist or its value is undefined.
(See also: Difference between undefi...
.htaccess mod_rewrite - how to exclude directory from rewrite rule
...ries on my server from these rules, so they can become accessible. For now all requests are sent to index.php file.
6 Answ...
What is the difference between client-side and server-side programming?
...php echo 42; ?>;
alert(baz);
</script>
Step 1, PHP executes all code between <?php ?> tags. The result is this:
<script type="text/javascript">
var foo = 'bar';
var baz = 42;
alert(baz);
</script>
The file_put_contents call did not result in anything,...
Create JSON-object the correct way
I am trying to create an JSON object out of a PHP array. The array looks like this:
5 Answers
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