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How do I limit the number of rows returned by an Oracle query after ordering?
... the original question, here's the query:
SELECT *
FROM sometable
ORDER BY name
OFFSET 20 ROWS FETCH NEXT 10 ROWS ONLY;
(For earlier Oracle versions, please refer to other answers in this question)
Examples:
Following examples were quoted from linked page, in the hope of preventing link rot.
Se...
find() with nil when there are no records
...
Yes, just do:
Challenge.find_by_id(10)
For Rails 4 and 5:
Challenge.find_by(id: 10)
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Understanding the ngRepeat 'track by' expression
I'm having difficulties understanding how the track by expression of ng-repeat in angularjs works. The documentation is very scarce: http://docs.angularjs.org/api/ng/directive/ngRepeat
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ORDER BY the IN value list
... (3,2),
(2,3),
(4,4)
) as x (id, ordering) on c.id = x.id
order by x.ordering
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how to remove X-Powered-By in ExpressJS [duplicate]
I want to remove X-Powered-By for Security,Save Bandwidth in ExpressJS(node.js). how to do it?
it could be filter(app.use) ?
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Passing Objects By Reference or Value in C#
In C#, I have always thought that non-primitive variables were passed by reference and primitive values passed by value.
7 ...
Relative frequencies / proportions with dplyr
...rs data, how do I calculate the relative frequency of number of gears by am (automatic/manual) in one go with dplyr ?
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Simultaneously merge multiple data.frames in a list
...concise syntax:
library(tidyverse)
list(x, y, z) %>% reduce(left_join, by = "i")
# A tibble: 3 x 4
# i j k l
# <chr> <int> <int> <int>
# 1 a 1 NA 9
# 2 b 2 4 NA
# 3 c 3 5 7
You can also perform other joins, such as a...
Swift: Pass array by reference?
...nt to pass my Swift Array account.chats to chatsViewController.chats by reference (so that when I add a chat to account.chats , chatsViewController.chats still points to account.chats ). I.e., I don't want Swift to separate the two arrays when the length of account.chats changes.
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Retrieving the last record in each group - MySQL
...ies:
WITH ranked_messages AS (
SELECT m.*, ROW_NUMBER() OVER (PARTITION BY name ORDER BY id DESC) AS rn
FROM messages AS m
)
SELECT * FROM ranked_messages WHERE rn = 1;
Below is the original answer I wrote for this question in 2009:
I write the solution this way:
SELECT m1.*
FROM messages...