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How does zip(*[iter(s)]*n) work in Python?
... zip(), and it pulls an item from the iterator each time.
x = iter([1,2,3,4,5,6,7,8,9])
print zip(x, x, x)
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edited Dec 14 '10 at 9:29
answered Dec 14 '10 at 9:23
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var list = (from t in ctn.Items
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