大约有 900 项符合查询结果（耗时：0.0183秒） [XML]
Numpy first occurrence of value greater than existing value
...timeit np.nonzero(aa>N/2)[0][0]
# Output
100000 loops, best of 3: 5.97 µs per loop
10000 loops, best of 3: 46.3 µs per loop
10000 loops, best of 3: 154 µs per loop
10000 loops, best of 3: 154 µs per loop
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Set breakpoint in C or C++ code programmatically for gdb on Linux
... answered Dec 1 '10 at 16:22
Håvard SHåvard S
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Getting error while sending email through Gmail SMTP - “Please log in via your web browser and then
...wered Sep 9 '15 at 0:55
H AßdøµH Aßdøµ
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How to find the foreach index?
... edited Dec 14 '17 at 3:16
buræquete
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answered Sep 26 '08 at 18:25
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Extract first item of each sublist
...t numpy-way, transforming the array:
%timeit list(np.array(lst).T[0])
4.9 µs ± 163 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
Fully native using list comprehension (as explained by @alecxe):
%timeit [item[0] for item in lst]
379 ns ± 23.1 ns per loop (mean ± std. dev. of 7 ...
UnicodeDecodeError when redirecting to file
...n when redirected to a file.
#coding: utf8
import sys
uni = u'αßΓπΣσµτΦΘΩδ∞φ'
print >>sys.stderr,sys.stdout.encoding
print uni
Output (run directly from terminal)
cp437
αßΓπΣσµτΦΘΩδ∞φ
Python correctly determined the encoding of the terminal.
Output (redirec...
Pandas - Get first row value of a given column
...ter than using .iloc:
In [1]: %timeit -n 1000 df['Btime'].values[20]
5.82 µs ± 142 ns per loop (mean ± std. dev. of 7 runs, 1000 loops each)
In [2]: %timeit -n 1000 df['Btime'].iloc[20]
29.2 µs ± 1.28 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
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How to add a button to UINavigationBar?
...red Mar 23 '10 at 23:45
Mads MobækMads Mobæk
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Pandas conditional creation of a series/dataframe column
...map( lambda x: 'red' if x == 'Z' else 'green')
1000 loops, best of 3: 239 µs per loop
1000 loops, best of 3: 523 µs per loop
1000 loops, best of 3: 263 µs per loop
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Getting a map() to return a list in Python 3.x
...imeit -r5 ordinals = list(range(45))
... list(map(chr, ordinals))
...
3.91 µs ± 60.2 ns per loop (mean ± std. dev. of 5 runs, 100000 loops each)
>>> %%timeit -r5 ordinals = list(range(45))
... [*map(chr, ordinals)]
...
3.84 µs ± 219 ns per loop (mean ± std. dev. of 5 runs, 100000 loo...