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Fancybox doesn't work with jQuery v1.9.0 [ f.browser is undefined / Cannot read property 'msie' ]

Fancybox breaks with the new jQuery v1.9.0. 4 Answers 4 ...
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Ruby: Merging variables in to a string

... answered Feb 16 '09 at 21:42 Mike WoodhouseMike Woodhouse 47.6k1212 gold badges8585 silver badges123123 bronze badges ...
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Is there any way to prevent input type=“number” getting negative values?

... Use the min attribute like this: <input type="number" min="0"> share | improve this answer | follow | ...
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how to find host name from IP with out login to the host

... Use nslookup nslookup 208.77.188.166 ... Non-authoritative answer: 166.188.77.208.in-addr.arpa name = www.example.com. share | improve this ...
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Cluster analysis in R: determine the optimal number of clusters

... 1024 If your question is how can I determine how many clusters are appropriate for a kmeans analysi...
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Determine .NET Framework version for dll

...t the source code because I believe it has been upgraded to Visual Studio 2008 and changed to .NET framework version 3.5. 1...
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How do you convert a byte array to a hexadecimal string, and vice versa?

... 1402 Either: public static string ByteArrayToString(byte[] ba) { StringBuilder hex = new StringBu...
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How to trim a string to N chars in Javascript?

... Why not just use substring... string.substring(0, 7); The first argument (0) is the starting point. The second argument (7) is the ending point (exclusive). More info here. var string = "this is a string"; var length = 7; var trimmedString = string.substring(0, length); ...
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How can I implode an array while skipping empty array items?

...ode('-', array_filter($array)); Obviously this will not work if you have 0 (or any other value that evaluates to false) in your array and you want to keep it. But then you can provide your own callback function. share ...
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Logic to test that 3 of 4 are True

... (§4.7/4) indicates that converting bool to int gives the expected values 0 or 1. In Java and C#, you can use the following construct: if ((a?1:0) + (b?1:0) + (c?1:0) + (d?1:0) == 3) ... share | ...