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Acronyms in CamelCase [closed]
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André Chalella
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answered Mar 20 '13 at 14:35
Apollo SOFTWAREApoll...
How do I concatenate or merge arrays in Swift?
If there are two arrays created in swift like this:
12 Answers
12
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Localization of DisplayNameAttribute
I am looking for a way to localize properties names displayed in a PropertyGrid. The property's name may be "overriden" using the DisplayNameAttribute attribute. Unfortunately attributes can not have non constant expressions. So I can not use strongly typed resources such as:
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How to sort two lists (which reference each other) in the exact same way
...the above may sacrifice speed for terseness; the in-place version, which takes up 3 lines, is a tad faster on my machine for small lists:
>>> %timeit zip(*sorted(zip(list1, list2)))
100000 loops, best of 3: 3.3 us per loop
>>> %timeit tups = zip(list1, list2); tups.sort(); zip(*tu...
Is there a way to pass the DB user password into the command line tool mysqladmin?
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Ethan AllenEthan Allen
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Hibernate Criteria returns children multiple times with FetchType.EAGER
... OrderTransactions and I mapped it with a one-to-many Hibernate mapping like so:
8 Answers
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How is null + true a string?
...ect a single best operator, a binding-time error occurs.
So, let's walk through this in turn.
X is the null type here - or not a type at all, if you want to think of it that way. It's not providing any candidates. Y is bool, which doesn't provide any user-defined + operators. So the first step...
how to get an uri of an image resource in android
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The format is:
"android.resource://[package]/[res id]"
[package] is your package name
[res id] is value of the resource ID, e.g. R.drawable.sample_1
to stitch it together, use
Uri path = Uri.parse("android.resource://your.package.name/" + R.drawable.sample_1)...
How to convert a clojure keyword into a string?
In my application I need to convert clojure keyword eg. :var_name into a string "var_name". Any ideas how that could be done?
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Get the Row(s) which have the max count in groups using groupby
... a 3
1 MM1 S1 n 2
2 MM1 S3 cb 5
3 MM2 S3 mk 8
4 MM2 S4 bg 10
5 MM2 S4 dgd 1
6 MM4 S2 rd 2
7 MM4 S2 cb 2
8 MM4 S2 uyi 7
In [2]: df.groupby(['Mt'], sort=False)['count'].max()
Out[2]:
Mt
S1 3
S3 8
S4 10
S2 ...