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Find unique rows in numpy.array
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As of NumPy 1.13, one can simply choose the axis for selection of unique values in any N-dim array. To get unique rows, one can do:
unique_rows = np.unique(original_array, axis=0)
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vs
...out the BOM. A free editor that can is Notepad++. On the program menu bar, select "Encoding > Encode in UTF-8 without BOM". You can also open files and re-save them in UTF-8 using "Encoding > Convert to UTF-8 without BOM".
More on the Byte Order Mark (BOM) at Wikipedia.
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C# Convert List to Dictionary
...other way to deal with duplicate is you can do like this
var dic = slist.Select((element, index)=> new{element,index} )
.ToDictionary(ele=>ele.index.ToString(), ele=>ele.element);
or
easy way to do is
var res = list.ToDictionary(str => str, str=> str);
but mak...
nodeValue vs innerHTML and textContent. How to choose?
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innerText is roughly what you would get if you selected the text and copied it. Elements that are not rendered are not present in innerText.
textContent is a concatenation of the values of all TextNodes in the sub-tree. Whether rendered or not.
Here is a great post det...
What is the equivalent of “android:fontFamily=”sans-serif-light" in Java code?
...ng this,
For Custom font:
TextView tv = ((TextView) v.findViewById(R.id.select_item_title));
Typeface face=Typeface.createFromAsset(getAssets(),"fonts/mycustomfont.ttf");
tv.setTypeface(face);
For Default font:
tv.setTypeface(Typeface.create("sans-serif-medium",Typeface.NORMAL));
These ar...
application/x-www-form-urlencoded or multipart/form-data?
...will fail.
The key is to choose an encoding and a boundary such that your selected boundary characters cannot appear in the encoded output. One simple solution is to use base64 (do not use raw binary). In base64 3 arbitrary bytes are encoded into four 7-bit characters, where the output character se...
What is the easiest way to disable/enable buttons and links (jQuery + Bootstrap)
... var $this = $(this);
if($this.is('input, button, textarea, select'))
this.disabled = state;
else
$this.toggleClass('disabled', state);
});
}
});
// Disabled on all:
$('input, button, a').disable(true);
// Enabled on all:
$('input,...
CSS I want a div to be on top of everything
...ou need a non-static positioning scheme.
Add position:relative; to a rule selecting the element you want to be on top
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A definitive guide to API-breaking changes in .NET
...d resolution will no longer fail, but a different overload will be quietly selected by the compiler. In practice, however, it is very hard to run into this case without carefully constructing method signatures to deliberately cause it.
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Pass arguments to Constructor in VBA
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This is cleaner than the selected answer.
– Mickey Perlstein
Jan 1 '14 at 13:15
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