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模拟器启动失败:找不到 msvcp140.dll - App Inventor 2 中文网 - 清泛IT社...
msvcp140.dll 及相关的微软的运行环境安装即可:
https://aka.ms/vs/16/release/vc_redist.x64.exe
https://aka.ms/vs/16/release/vc_redist.x86.exe
菜单的背景颜色 - C/C++ - 清泛网 - 专注C/C++及内核技术
菜单的背景颜色菜单栏在对话框窗口里显示菜单栏像工具栏一样,菜单栏在按件面板里没有对应的选项,但有一个菜单控件类CMenu,所以如果想要在对话框里显示...在对话框窗口里显示菜单栏
像工具栏一样,菜单栏在按件面板...
Notifier 通知扩展:功能强大的Android通知管理工具,支持通知通道、意图、...
...sion.POST_NOTIFICATIONS 权限。必须授予此权限才能显示通知。安装应用程序后,权限默认设置为 denied(拒绝)。Manifest.permission.POST_NOTIFICATIONS 被分类为危险(保护级别:dangerous)。这意味着用户必须明确授予权限。他们可以通过应...
虚拟机安装CentOS出错:EDD:Error 8000 reading sector 2106934 - 更多技术...
虚拟机安装CentOS出错:EDD:Error 8000 reading sector 2106934现象:EDD:Error 8000 reading sector 2106934No DEFAULT or UI configuration directive found!boot:Getting closer!When i ...现象:
EDD:Error 8000 reading sector 2106934
No DEFAULT or UI configuration directive found!
boot:
...
nsis安装、卸载时如何判断程序是否正在运行 并提示关闭? - 更多技术 - 清...
nsis安装、卸载时如何判断程序是否正在运行 并提示关闭?;--------------------------------------------------------------!include logiclib.nshFindProcDLL::FindProc "Test.exe"StrCmp $R0...
;--------------------------------------------------------------
!include logiclib.nsh
Find...
错误:缺少一个项目子类型。 子类型: 此安装不支持“{C089C8C0-30E0-4E22-8...
解决方法:下载安装Microsoft Visual Studio 2012 SDKhttp://www.microsoft.com/en-us/download/confirmation.aspx?id=30668
C++实现一款简单完整的聊天室服务器+客户端 - C/C++ - 清泛网 - 专注C/C++及内核技术
C++实现一款简单完整的聊天室服务器+客户端Linux下select函数实现的聊天服务器消息缓冲区类MessageBuffer,接收线程将受到的消息放入缓冲区,发送线程从缓冲区中取出消息MessageBuffe...目录:
Linux下select函数实现的聊天服务器
基...
Call PowerShell script PS1 from another PS1 script inside Powershell ISE
I want call execution for a myScript1.ps1 script inside a second myScript2.ps1 script inside Powershell ISE.
11 Answers
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What is the difference between PS1 and PROMPT_COMMAND
...d as a command to execute before
the printing of each primary prompt ($PS1).
I never used it, but I could have used this back when I only had sh.
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How to determine the current shell I'm working on
... example (which frequently happens).
Thus your second question of whether ps output will do is answered with "not always".
echo $0 - will print the program name... which in the case of the shell is the actual shell.
ps -ef | grep $$ | grep -v grep - this will look for the current process ID in t...
