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Stra<em>nem>gest la<em>nem>guage feature
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that's because a[10] mea<em>nem>s *(a+10) ... <em>a<em>nem>dem> 10[a] mea<em>nem>s *(10+a) :)
– Michel Goka<em>nem>
Ja<em>nem> 3 '10 at 14:50
77
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How to match “a<em>nem>ythi<em>nem>g up u<em>nem>til this seque<em>nem>ce of characters” i<em>nem> a regular expressio<em>nem>?
...s p<em>osem>sible to satisfy.
Whe<em>nem> usi<em>nem>g .+?, i<em>nem>stead of matchi<em>nem>g all at o<em>nem>ce <em>a<em>nem>dem> goi<em>nem>g back for
other co<em>nem>ditio<em>nem>s (if a<em>nem>y), the e<em>nem>gi<em>nem>e will match the <em>nem>ext characters by
step u<em>nem>til the subseque<em>nem>t part of the regex is matched (agai<em>nem> if a<em>nem>y).
This is the u<em>nem>-greedy, mea<em>nem>i<em>nem>g match the fewest p<em>osem>si...
How to compare a local git bra<em>nem>ch with its remote bra<em>nem>ch?
How ca<em>nem> I see the diff betwee<em>nem> a local bra<em>nem>ch <em>a<em>nem>dem> a remote bra<em>nem>ch?
22 A<em>nem>swers
22
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TypeScript Objects as Dictio<em>nem>ary types as i<em>nem> C#
...te<em>nem>tial gotchas with this approach, the big o<em>nem>e bei<em>nem>g that there's <em>nem>o safe <em>a<em>nem>dem> easy way to iterate through all the members. This code, for i<em>nem>sta<em>nem>ce, shows that map co<em>nem>tai<em>nem>s two members: (<a<em>nem>y>Object.prototype).somethi<em>nem>g = fu<em>nem>ctio<em>nem>(){}; class Customer{} var map: { [email: stri<em>nem>g]: Custo...
Profili<em>nem>g Vim startup time
...with how lo<em>nem>g Vim takes to start <em>nem>ow, so I’d like to profile its startup <em>a<em>nem>dem> see which of the ma<em>nem>y plugi<em>nem>s I have are respo<em>nem>sible.
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I have 2 dates i<em>nem> PHP, how ca<em>nem> I ru<em>nem> a foreach loop to go through all of th<em>osem>e days?
I'm starti<em>nem>g with a date 2010-05-01 <em>a<em>nem>dem> e<em>nem>di<em>nem>g with 2010-05-10 . How ca<em>nem> I iterate through all of th<em>osem>e dates i<em>nem> PHP?
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Query to list <em>nem>umber of records i<em>nem> each table i<em>nem> a database
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If you're usi<em>nem>g SQL Server 2005 <em>a<em>nem>dem> up, you ca<em>nem> also use this:
SELECT
t.<em>Nem>AME AS Table<em>Nem>ame,
i.<em>nem>ame as i<em>nem>dex<em>Nem>ame,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(...
Accept fu<em>nem>ctio<em>nem> as parameter i<em>nem> PHP
...s goi<em>nem>g to a<em>nem>swer, but wa<em>nem>ted to fi<em>nem>d some docume<em>nem>tatio<em>nem> to li<em>nem>k to first, <em>a<em>nem>dem> did<em>nem>'t k<em>nem>ow what it was called exactly. Ah well, <em>nem>ow I'll k<em>nem>ow for whe<em>nem> I <em>nem>eed to do this as well. Tha<em>nem>ks.
– Rob
Apr 23 '10 at 17:01
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Regular Expressio<em>nem>s <em>a<em>nem>dem> <em>nem>egati<em>nem>g a whole character group [duplicate]
...ples I gave wo<em>nem>'t match 'ab' it's true but they also wo<em>nem>'t match 'a' alo<em>nem>e <em>a<em>nem>dem> I <em>nem>eed them to. Is there some simple way to do this?
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How to break out from a ruby block?
...fers co<em>nem>trol out of the block, out of the iterator that i<em>nem>voked the block, <em>a<em>nem>dem> to the first expressio<em>nem> followi<em>nem>g the i<em>nem>vocatio<em>nem> of the iterator:
f.each do |li<em>nem>e| # Iterate over the li<em>nem>es i<em>nem> file f
break if li<em>nem>e == "quit\<em>nem>" # If this break stateme<em>nem>t is executed...
puts eval(li<em>nem>e)
e<em>nem>...