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Is multiplication and division using shift operators in C actually faster?
Multiplication and division can be achieved using bit operators, for example
19 Answers
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No increment operator (++) in Ruby? [duplicate]
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Ruby has no pre/post increment/decrement operator. For instance, x++ or x-- will fail to parse. More importantly, ++x or --x will do nothing! In fact, they behave as multiple unary prefix operators: -x == ---x == -----x == ...... To increment a number, simply write x += 1.
Taken from "Th...
Java; String replace (using regular expressions)?
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ah... but you missed collapsing the "5 * x" to "5x"
– James Curran
Mar 10 '09 at 20:53
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How to copy a selection to the OS X clipboard
I have an area selected in Vim. How can I copy it into the OS X clipboard?
27 Answers
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Simple way to calculate median with MySQL
...fully not too slow) way to calculate the median with MySQL? I've used AVG(x) for finding the mean, but I'm having a hard time finding a simple way of calculating the median. For now, I'm returning all the rows to PHP, doing a sort, and then picking the middle row, but surely there must be some sim...
Why do I need 'b' to encode a string with Base64?
Following this python example , I encode a string as Base64 with:
5 Answers
5
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Why can't I declare static methods in an interface?
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Good answer, though "approximately equivalent" ROFLMAO xD I would have put it more like "somewhat resembles".
– Timo
May 18 '15 at 12:51
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git pull while not in a git directory
Let's say I have a directory, /X/Y , which is a git repository. Is it possible to somehow call a command like git pull from inside /X , but targeting the /X/Y directory?
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How do JavaScript closures work?
How would you explain JavaScript closures to someone with a knowledge of the concepts they consist of (for example functions, variables and the like), but does not understand closures themselves?
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Comparing two dictionaries and checking how many (key, value) pairs are equal
... should have said that :)
Maybe something like this:
shared_items = {k: x[k] for k in x if k in y and x[k] == y[k]}
print len(shared_items)
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