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What is the non-jQuery equivalent of '$(document).ready()'?

What is the non-jQuery equivalent of $(document).ready() ? 9 Answers 9 ...
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MySQL/Amazon RDS error: “you do not have SUPER privileges…”

...t allow the non-offending SQL statements in the file to be processed. From what I've read, RDS is choking on stored procedures in the dump file. Try creating a dump file without store procedures and see if that loads OK: mysqldump --routines=0 --triggers=0 --events=0 my_database -u my_username -p ...
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How to break a line of chained methods in Python?

... Not sure what justifies the extra indentation here; I think this solution reads just as well with the hanging lines indented just once and the trailing paren not at all. – Carl Meyer Jun 23 '15 a...
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What encoding/code page is cmd.exe using?

When I open cmd.exe in Windows, what encoding is it using? 6 Answers 6 ...
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HttpListener Access Denied

...to admin mode while it's running. Regarding UseShellExecute: it depends on what you're executing. I tested my code with "notepad.exe", it works fine without UseShellExecute = false – Thomas Levesque Oct 26 '10 at 12:05 ...
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How to toggle a value in Python

What is the most efficient way to toggle between 0 and 1 ? 17 Answers 17 ...
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Recover from git reset --hard?

...de. This means you are not actually pointing at a branch, but you can view what was checked in at the state of the entity (in this case a reflog entry). From that state, you can turn it into a "real" branch that you can go back to again by using git checkout -b new-branch-name. The book Pragmatic Ve...
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Get the value in an input text box

What are the ways to get and render an input value using jQuery? 12 Answers 12 ...
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How does Go compile so quickly?

...de the packages that you are importing directly (as those already imported what they need). This is in stark contrast to C/C++, where every single file starts including x headers, which include y headers etc. Bottom line: Go's compiling takes linear time w.r.t to the number of imported packages, whe...
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What is the purpose of the “final” keyword in C++11 for functions?

What is the purpose of the final keyword in C++11 for functions? I understand it prevents function overriding by derived classes, but if this is the case, then isn't it enough to declare as non-virtual your final functions? Is there another thing I'm missing here? ...