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How to use C++ in Go
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You can't quite yet from what I read in the FAQ:
Do Go programs link with C/C++ programs?
There are two Go compiler implementations, gc (the 6g program and friends) and gccgo. Gc uses a different calling convention and linker and can therefore only...
Automatic Retina images for web sites
...users without support simply see a normal DPI image. Definitely think it's ready for usage.
– andrewb
Apr 18 '16 at 3:04
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Application Loader: “Cannot proceed with delivery: an existing transporter instance is currently upl
...d was successfully uploaded on itunesConnect. This may be due to a build already created and being processed on the website as it does not allow multiple builds to be uploaded at once. Weird!!
– Som
Mar 24 '15 at 11:10
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Is it OK to leave a channel open?
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@Richard: Read the entire thread carefully. The author of Go gc and the author of gccgo say channel closes are not necessary, unless you are looking for a close. That's authoritative advice.
– peterSO
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Is MonoTouch now banned on the iPhone? [closed]
.... Love it or leave it, but quit crying about it. And just go buy a mac already...
– kirk.burleson
Jul 13 '10 at 1:56
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How do I move a single folder from one Subversion repository to another repository?
...d Jan 6 '09 at 19:10
Adam BellaireAdam Bellaire
95.7k1919 gold badges141141 silver badges159159 bronze badges
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What do 3 dots next to a parameter type mean in Java?
... This answer borrows heavily from kiswa's and Lorenzo's if I read the edits correctly.
– Matt Mitchell
Jul 22 '10 at 3:37
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What does the line “#!/bin/sh” mean in a UNIX shell script?
... that the magic number, it knows that it is dealing with a text script and reads until the next \n (there is a limit, but it escapes me atm). Having identified the interpreter (the first argument after the shebang) it will call the interpreter.
Other files also have magic numbers. Try looking at a...
Get an OutputStream into a String
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Save yourself a year of your life and read through all the common's APIs so when you encounter a problem, you can unleash a fully tested and community owned solution.
– Bob Herrmann
Oct 20 '08 at 0:53
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Explain the encapsulated anonymous function syntax
...rrides the previous declaration. At runtime, the function declaration is already available and in this case, the one that is available is the one that alerts "false". For more info, read you don't know JS
– Saurabh Misra
Mar 7 '18 at 10:29
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