大约有 15,510 项符合查询结果（耗时：0.0164秒） [XML]
#if DEBUG vs. Conditional(“DEBUG”)
... you should pretty much never use either. If you really need something for testing and debugging, figure out a way to make that testability seperate from the actual production code.
Abstract the scenarios with mocking in unit tests, make one off versions of things for one off scenarios you want to ...
Best way to strip punctuation from a string
...ans("","")
regex = re.compile('[%s]' % re.escape(string.punctuation))
def test_set(s):
return ''.join(ch for ch in s if ch not in exclude)
def test_re(s): # From Vinko's solution, with fix.
return regex.sub('', s)
def test_trans(s):
return s.translate(table, string.punctuation)
def ...
Faster way to develop and test print stylesheets (avoid print preview every time)?
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I've just tested what @TylerH said in Firefox v68 and it works.
– StR
Aug 8 '19 at 14:55
add a comment
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How to return only the Date from a SQL Server DateTime datatype
...rked different methods of trimming off time from dates and this was the fastest method. Granted the difference was small, but it was clearly faster over a large # of executions.
– UnhandledExcepSean
Jul 3 '14 at 12:48
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PhoneGap: Detect if running on desktop browser
...this will cause problems using the phones browser... This is a solution to test on your desktop browser not your phones.
– sirmdawg
Nov 7 '12 at 4:44
7
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__init__ for unittest.TestCase
I'd like to add a couple of things to what the unittest.TestCase class does upon being initialized but I can't figure out how to do it.
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Cannot overwrite model once compiled Mongoose
... It can actually be useful to change a Schema after defining for testing schema migration code.
– Igor Soarez
Jan 28 '14 at 18:21
1
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How to check if a string contains a substring in Bash
...so note that you can reverse the comparison by just switching to != in the test. Thanks for the answer!
– Quinn Taylor
Jul 30 '09 at 17:14
65
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How can I check if a string represents an int, without using try/except?
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You have to test for BOTH cases: lambda s: s.isdigit() or (s.startswith('-') and s[1:].isdigit())
– rob
Aug 12 '09 at 13:39
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Algorithm to detect intersection of two rectangles?
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The standard method would be to do the separating axis test (do a google search on that).
In short:
Two objects don't intersect if you can find a line that separates the two objects. e.g. the objects / all points of an object are on different sides of the line.
The fun thing...