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How to flatten an ExpandoObject returned via JsonResult in asp.net mvc?
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Nice. You can also cast the dynamic on the fly: return new JsonResult(((ExpandoObject)someIncomingDynamicExpando).ToDictionary(item => item.Key, item => item.Value))
– joeriks
May 13 '12 at 17:13
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How to get a function name as a string?
...the above error, consider:
import inspect
import types
from typing import cast
this_function_name = cast(types.FrameType, inspect.currentframe()).f_code.co_name
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What is the difference between Collections.emptyList() and Collections.EMPTY_LIST
...t is probably always preferable. This way, you don't need to unnecessarily cast around within your code.
Collections.emptyList() intrinsically does the cast for you.
@SuppressWarnings("unchecked")
public static final <T> List<T> emptyList() {
return (List<T>) EMPTY_LIST;
}
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How to print a int64_t type in C
..._int = 999999999999999999;
printf("%" PRId64 "\n", my_int);
Or you could cast!
printf("%ld", (long)my_int);
printf("%lld", (long long)my_int); /* C89 didn't define `long long` */
printf("%f", (double)my_int);
If you're stuck with a C89 implementation (notably Visual Studio) you can perhaps use ...
Truncate Two decimal places without rounding
...our function will cause overflows. You should use Int64 if you really must cast it to an Integer. The question would be why you would want to incur that extra overhead anyway since Truncate returns Decimal integrals anyway. Just do something like: decimal step = (decimal)Math.Pow(10, precision); re...
Create instance of generic type in Java?
...error, while new Foo<Bar>(){}; doesn't? (Exception: "Class cannot be cast to ParameterizedType")
– Tim Kuipers
Dec 22 '13 at 14:52
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Is it possible to use the instanceof operator in a switch statement?
... Function instead of Runnable, pass the instance in as the parameter, then cast it when needed
– Novaterata
Jun 3 '19 at 22:07
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Convert from List into IEnumerable format
...plements IEnumerable<T>. It means that you do not have to convert or cast anything.
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How to supply value to an annotation from a Constant java
...nly the following:
Literals of primitive type and literals of type String
Casts to primitive types and casts to type String
[...] operators [...]
Parenthesized expressions whose contained expression is a constant expression.
Simple names that refer to constant variables.
Qualified names of the form...
Does Java read integers in little endian or big endian?
...oes exactly what you tell it, there's no ambiguity. In C you could always cast a "byte*" to a "long*" and de-reference it. Then you'd have to care about endianess. In Java there's no direct, ambiguous way to do that.
– Joachim Sauer
Dec 12 '08 at 22:02
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