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I don't remember my android debug.keystore password
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Usually the debug.keystore password is just "android".
You can delete it and Eclipse will automatically generate a new one, as described here.
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What should I do if two libraries provide a function with the same name generating a conflict?
... either of them you can wrap one of them up. That is compile another (statically linked!) library that does nothing except re-export all the symbols of the original except the offending one, which is reached through a wrapper with an alternate name. What a hassle.
Added later: Since qeek says he's t...
Should each and every table have a primary key?
...y, rethink your design: most probably, you are missing something. Why keep identical records?
In MySQL, the InnoDB storage engine always creates a primary key if you didn't specify it explicitly, thus making an extra column you don't have access to.
Note that a primary key can be composite.
If y...
Running Bash commands in Python
...h are commonly overlooked.
Prefer subprocess.run() over subprocess.check_call() and friends over subprocess.call() over subprocess.Popen() over os.system() over os.popen()
Understand and probably use text=True, aka universal_newlines=True.
Understand the meaning of shell=True or shell=False and ho...
What is the HTML tabindex attribute?
...…, "The tabindex attribute, if specified, must have a value that is a valid integer".
– Mark Amery
Mar 26 '17 at 20:46
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How to retrieve a module's path?
... # "print(os.getcwd())" still works fine
Traceback (most recent call last): # but __file__ doesn't exist if bar.py is running as main
File "/path2/bar.py", line 3, in <module>
print(__file__)
NameError: name '__file__' is not defined
Hope this helps. This caveat cost me a ...
TypeError: 'module' object is not callable
...'>
This is what the error message means:
It says module object is not callable, because your code is calling a module object. A module object is the type of thing you get when you import a module. What you were trying to do is to call a class object within the module object that happens to have...
'this' vs $scope in AngularJS controllers
...ers?"
Short answer:
this
When the controller constructor function is called, this is the controller.
When a function defined on a $scope object is called, this is the "scope in effect when the function was called". This may (or may not!) be the $scope that the function is defined on. So, ins...
Ruby: Calling class method from instance
In Ruby, how do you call a class method from one of that class's instances? Say I have
9 Answers
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converting drawable resource image into bitmap
...rgeIcon);
This is a great method of converting resource images into Android Bitmaps.
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