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No generic implementation of OrderedDictionary?
...mean license it and host it somewhere - no... it lives here on SO only for now.
– mattmc3
Mar 5 '13 at 3:43
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How do I check if the Java JDK is installed on Mac?
...ary/Java/JavaVirtualMachines/
Then run ls command in the terminal again. Now you can see the jdk version & package if exists in your computer.
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Click outside menu to close in jquery
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Nevermind, I didn't see the "one" function, now I understand why this works: api.jquery.com/one
– eselk
Apr 8 '13 at 22:15
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Why do some scripts omit the closing PHP tag, '?>'? [duplicate]
...ot of stuff with php, why should inject JS. I was fool then, and still one now. What was I thinking.
– Nafis Ahmad
Dec 1 '13 at 16:45
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tag vs tag
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@dholakiyaankit Please quote the source as well. Now people might think that, these are your own words.
– thefourtheye
Dec 25 '13 at 9:55
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C# : 'is' keyword and checking for Not
...ng was not a particular type. I've done it (!(child is Something)) forever now, but I thought I'd make sure there wasn't a better way.
– Hugoware
May 1 '09 at 14:43
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Convert decimal to binary in python [duplicate]
....5.2 TypeError: non-empty format string passed to object.__format__ ahh - now i got it, what you meant: ```>>> "{0:b}".format(47) ---> '101111'
– Josef Klotzner
Oct 10 '19 at 18:58
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How do I see the commit differences between branches in git?
...e an option if both branches contain commits that the other doesn't? Right now, you have to flip the arguments and run it both ways to see commits the other branch doesn't contain.
– Elliott Slaughter
Feb 10 '16 at 17:52
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Map over object preserving keys
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I know this is old, but now Underscore has a new map for objects :
_.mapObject(object, iteratee, [context])
You can of course build a flexible map for both arrays and objects
_.fmap = function(arrayOrObject, fn, context){
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Unresolved reference issue in PyCharm
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Then make sure to add add sources to your PYTHONPATH:
Now imports will be resolved:
This way, you can add whatever you want as a source root, and things will simply work. If you unmarked it as a source root however, you will get an ...
