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Django optional url parameters
I have a Django URL like this:
7 Answers
7
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Is quoting the value of url() really necessary?
...ust need to be the same character.
If you have special characters in your URL, you should use quotes or escape the characters (see below).
Syntax and basic data types
The format of a URI value is 'url(' followed by optional white space followed by an optional single quote (') or double quote (...
How do I parse a URL query parameters, in Javascript? [duplicate]
In Javascript, how can I get the parameters of a URL string (not the current URL)?
2 Answers
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How to Get the Current URL Inside @if Statement (Blade) in Laravel 4?
I am using Laravel 4. I would like to access the current URL inside an @if condition in a view using the Laravel's Blade templating engine but I don't know how to do it.
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How can I get my webapp's base URL in ASP.NET MVC?
How can I quickly determine what the root URL is for my ASP.NET MVC application? I.e., if IIS is set to serve my application at http://example.com/foo/bar , then I'd like to be able to get that URL in a reliable way that doesn't involve getting the current URL from the request and chopping it up i...
Navigation in django
...t;ul id="nav">
<li>{% block nav-home %}<a href="{% url home %}">Home</a>{% endblock %}</li>
<li>{% block nav-about %}<a href="{% url about %}">About</a>{% endblock %}</li>
<li>{% block nav-contact %}<a hr...
Get escaped URL parameter
I'm looking for a jQuery plugin that can get URL parameters, and support this search string without outputting the JavaScript error: "malformed URI sequence". If there isn't a jQuery plugin that supports this, I need to know how to modify it to support this.
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How can I find where I will be redirected using cURL?
I'm trying to make curl follow a redirect but I can't quite get it to work right. I have a string that I want to send as a GET param to a server and get the resulting URL.
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How do I combine a background-image and CSS3 gradient on the same element?
...iple backgrounds!
body {
background: #eb01a5;
background-image: url("IMAGE_URL"); /* fallback */
background-image: url("IMAGE_URL"), linear-gradient(#eb01a5, #d13531); /* W3C */
}
These 2 lines are the fallback for any browser that doesn't do gradients.
See notes for stacking ...
Get fragment (value after hash '#') from a URL in php [closed]
How can i select the fragment after the '#' symbol in my URL using PHP?
The result that i want is "photo45".
10 Answers
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